We will see that the solution in the given interval is: x = 0.349 radians.
<h3>How to solve equations with the variable in the argument of a cosine?</h3>
We want to solve:
cos(3*x) = 1/2
Here we must use the inverse cosine function, Acos(x). Remember that:
cos(Acos(x)) = Acos(cos(x)) = x.
If we apply that in both sides, we get:
Acos( cos(3x) ) = Acos(1/2)
3*x = Acos(1/2)
x = Acos(1/2)/3 = 0.349
So x is equal to 0.349 radians, which belongs to the given interval.
If you want to learn more about trigonometry, you can read:
brainly.com/question/8120556
Answer:
<h2>A. (0, 4)</h2>
Step-by-step explanation:
The equation of a circle:
(h, k) - center
r - radius
We have the equation:
h = 0, k = 4, r = 5
Answer:
(a) k'(0) = f'(0)g(0) + f(0)g'(0)
(b) m'(5) = 
Step-by-step explanation:
(a) Since k(x) is a function of two functions f(x) and g(x) [ k(x)=f(x)g(x) ], so for differentiating k(x) we need to use <u>product rule</u>,i.e., ![\frac{\mathrm{d} [f(x)\times g(x)]}{\mathrm{d} x}=\frac{\mathrm{d} f(x)}{\mathrm{d} x}\times g(x) + f(x)\times\frac{\mathrm{d} g(x)}{\mathrm{d} x}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cmathrm%7Bd%7D%20%5Bf%28x%29%5Ctimes%20g%28x%29%5D%7D%7B%5Cmathrm%7Bd%7D%20x%7D%3D%5Cfrac%7B%5Cmathrm%7Bd%7D%20f%28x%29%7D%7B%5Cmathrm%7Bd%7D%20x%7D%5Ctimes%20g%28x%29%20%2B%20f%28x%29%5Ctimes%5Cfrac%7B%5Cmathrm%7Bd%7D%20g%28x%29%7D%7B%5Cmathrm%7Bd%7D%20x%7D)
this will give <em>k'(x)=f'(x)g(x) + f(x)g'(x)</em>
on substituting the value x=0, we will get the value of k'(0)
{for expressing the value in terms of numbers first we need to know the value of f(0), g(0), f'(0) and g'(0) in terms of numbers}{If f(0)=0 and g(0)=0, and f'(0) and g'(0) exists then k'(0)=0}
(b) m(x) is a function of two functions f(x) and g(x) [ 
]. Since m(x) has a function g(x) in the denominator so we need to use <u>division rule</u> to differentiate m(x). Division rule is as follows : 
this will give <em>
</em>
on substituting the value x=5, we will get the value of m'(5).
{for expressing the value in terms of numbers first we need to know the value of f(5), g(5), f'(5) and g'(5) in terms of numbers}
{NOTE : in m(x), g(x) ≠ 0 for all x in domain to make m(x) defined and even m'(x) }
{ NOTE : 
}
9514 1404 393
Answer:
the listed sequences have no common difference(s)
Step-by-step explanation:
The differences in the first sequence are ...
8, 10, -1, 19
These values are not equal, so there is no common difference.
__
The differences in the second sequence are ...
-3, 3, -3, 3
These values are not equal, so there is no common difference.
_____
The difference is the difference between a term value and the one before.
1 -(-7) = 8
3 -6 = -3
Answer: Hello your question some data but i will provide a general solution based on the scope of your question making some suggestions as well
answer : Summation of displacements ( back and forth distance ) / Number of Runners
Step-by-step explanation:
Given that ; the aim of the race is to raise money
The number of miles/ distance covered will determine how much money that would be raised
Formula to resolve the problem = Summation of displacements ( back and forth distance ) / Number of Runners
<em>Lets assume: ( example ) </em>
<em> Distance between the Park and the City hall is = 6 miles </em>
<em>Number of runners = 4</em>
<em>Given that the runners Run from the Park to the City hall and then run back</em>
<em>Total miles covered by each runner = ( 6 + 6 )/ 4 = 12/4 = 3 miles </em>
