The correct answer is B, sorry if it wasn't correct.
Given the following table that gives data from a linear function:
![\begin {tabular} {|c|c|c|c|} Temperature, $y = f(x)$ (^\circ C)&0&5&20 \\ [1ex] Temperature, $x$ (^\circ F)&32&41&68 \\ \end {tabular}](https://tex.z-dn.net/?f=%5Cbegin%20%7Btabular%7D%0A%7B%7Cc%7Cc%7Cc%7Cc%7C%7D%0ATemperature%2C%20%24y%20%3D%20f%28x%29%24%20%28%5E%5Ccirc%20C%29%260%265%2620%20%5C%5C%20%5B1ex%5D%0ATemperature%2C%20%24x%24%20%28%5E%5Ccirc%20F%29%2632%2641%2668%20%5C%5C%20%0A%5Cend%20%7Btabular%7D)
The formular for the function can be obtained by choosing two points from the table and using the formular for the equation of a straight line.
Recall that the equation of a straight line is given by

Using the points (32, 0) and (41, 5), we have:
They both would need to get two toppings to cost the same amount which would be $8.60
r > 0 = r is greater than 0
r ≤ 8 = r is less than and equal to 8
0 ≤ r ≤ 8
Set up the following equations:


x represents car A's speed, and y represents car B's speed.
We'll use elimination to solve this system of equations. Multiply the first equation by 7:


Combine both equations:

Divide both sides by 28 to get x by itself:

The speed of car A is
80 mph.Since we now know the value of one of the variables, we can plug it into the first equation:


Subtract 160 from both sides.

Divide both sides by 2 to get y by itself:

The speed of car B is
60 mph.