I really need help in math! Any is appreciated!

Please answer right away

fenix001 [56]

The coefficient of determination is the first one. I'm pretty sure.

6 0

3 years ago

How can I find the slope to this I need help

Dmitrij [34]

Answer:

Your slope is -1

Step-by-step explanation:

Find the change in x and the change in y and put it in change in y over change in x.

Δx = -1 - -2 = 1

Δy = -1 - 0 = -1

Slope = rise over run = Change in y over change in x = Δy/Δx = -1/1

Therefore the slope is -1/1 which is written as just -1

7 0

3 years ago

Can you guys please help me? This is limited. (5v)^2/3 and the second one radical 10k

Eddi Din [679]

Here’s the answer for the first question and the second one stays 10k

7 0

3 years ago

A mug is 1/8 full. The mug contains 1/6 of a cup of water. Find the capacity of the mug. Write the answer as a fration or mixed

Andre45 [30]

Answer:

The capacity of the mug = $1\frac{1}{3}$ cups

Step-by-step explanation:

Given - A mug is 1/8 full. The mug contains 1/6 of a cup of water.

To find - Find the capacity of the mug. Write the answer as a fraction or mixed number

Proof -

Let the capacity of water = x

Given that,

A mug is $\frac{1}{8}$ full of water

⇒Total cups of water in the mug = $\frac{1}{8} x$

Now,

Given that, The mug contains $\frac{1}{6}$ of a cup of water.

∴ we get

$\frac{1}{8} x$ = $\frac{1}{6}$

⇒x = $\frac{1}{6}$ × 8

= $\frac{8}{6}$

= $\frac{4}{3}$ = $1\frac{1}{3}$

⇒x = $1\frac{1}{3}$

∴ we get

The capacity of the mug = $1\frac{1}{3}$ cups

8 0

3 years ago

George and Riley are selling fruit for a school fundraiser. Customers can buy small boxes of oranges and large boxes of oranges.

worty [1.4K]

The cost of small box of oranges is $7.

The cost of large box of oranges is $13.

Step-by-step explanation:

It is given that,

3 small boxes of oranges and 14 large boxes of oranges for a total of $203.

11 small boxes of oranges and 11 large boxes of oranges for a total of $220.

Let us take,

The cost of small box of oranges = x
The cost of large box of oranges = y

The system of equations are framed as :

3x + 14y = 203 ---------(1)

11x + 11y = 220 ---------(2)

To solve these equations for x and y values :

Multiply equation (1) by 11 and equation (2) by 3

Subtract eq(2) from eq(1),

33x + 154y = 2233

- (33x + 33y = 660)

121 y = 1573

⇒ y = 1573 / 121

⇒ y = 13

∴ The cost of large box of oranges is $13.

Substitute y=13 in the eq(1),

⇒ 3x + 14(13) = 203

⇒ 3x + 182 = 203

⇒ 3x = 203 - 182

⇒ 3x = 21

⇒ x = 21 / 3

⇒ x = 7

∴ The cost of small box of oranges is $7.

7 0

3 years ago