Hey there!
2/3 = a/30
First: you have to CROSS MULTIPLY the given numbers
2(30) = 3(a)
2(30) = 60
3(a) = 3a
New EQUATION: 3a = 60
Second: DIVIDE 3 to BOTH SIDES
3a/3 = 60/3
CANCEL out: 3/3 because that gives you 1
KEEP: 60/3 because that helps you solve for your a-value
60/3 = a
60/3 = 20
Therefore, your answer is: a = 20
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
Divide 1/2 by 1/8 by doing Keep change flip. 1/2 divided by 1/8 turns to 1/2 x 8/1 =9/2 and then divide 9/2 like this 9 divided by 2= 2 1/2
Answer: so i think for part a , the first term is a subscrpit 0 which is 10. Then the formula for any term in the sequence is Ao x R ^n. So R =2 so
1st term = 10 ( 2^0)= 1
2nd term = 10 (2^1) =20
3rd term = 10 (2^2)= 40
4th = 80
5th = 160
Part B
The limit as n approaches infinity for a sub n when R is 0, 1 and 2. THE LIMIT FOR R of 0, 1 and 2 is infinity.
Part C...i will have to research...sorry
Step-by-step explanation:
Answer:
After 16 years …mr James age =4X+16 and his son's age will be X+16
As per the question in 16 years his age will be 2 twice
(4X+16)=2(X+16)so by simplifying this we will get 2X=16..and X=16/2=8
Step-by-step explanation:
Answer:
x = 0, 51
Step-by-step explanation:
<u>→First, you need to factor out the GCF (Greatest Common Factor), which is -0.03x, like so:</u>
-0.03x (x - 51) = 0
<u>→Remove the -0.03 by divide it by both sides:</u>
x(x - 51) = 0
<u>→Separate each, like so:</u>
x = 0
x - 51 = 0
<u>→Solve for x:</u>
x - 51 = 0
x = 51
<u>Your solutions are, 0 and 51.</u>
