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BlackZzzverrR [31]
3 years ago
14

Ana es una vendedora de bombones tenía 295 cajas y ha vendido 67 de ellas si cada caja contiene 24 bombones¿ cuántos bombones le

quedaron sin vender?
Mathematics
1 answer:
Sergeu [11.5K]3 years ago
5 0

Answer:

the number of chocolates remains unsold is 5,472

Step-by-step explanation:

The computation of the number of chocolates remains unsold is given below:

= (Total boxes - sold boxes) × number of chocolates in each box

= (295 - 67) × 24

= 228 × 24

= 5,472 chocolates

hence, the number of chocolates remains unsold is 5,472

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Lynna [10]

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Step-by-step explanation:

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4 years ago
I need help figuring out what: f(r-2)=6x+7 is
Andrej [43]

Answer:

f(r-2) = 6r -5

Step-by-step explanation:

f(r-2) is another notation for x = r-2

so we’ll plug in r-2 for x and solve:

f(r-2) = 6(r-2)+7

f(r-2) = 6r -12 +7

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3 years ago
A water tank has a diameter of 15 ft and is 22 ft high. a. What is the volume of the tank in ft?? b. In m?? c. In cm?
rodikova [14]

Answer:

a) V = 3887.72 ft^{3}

b)V = 104.97 m^{3}

c)V = 104,968,468.538 cm^{3}

Step-by-step explanation:

A tank has the format of a cylinder.

The volume of the cylinder is given by:

V = \pi r^{2}h

In which r is the radius and h is the heigth.

The problem states that the diameter is measured to be 15.00 ft. The radius is half the diameter. So, for this tank

r = \frac{15}{2} = 7.50 ft

The height of the tank is 22 ft, so h = 22.

a) Volume of the tank in ft^{3}:

V = \pi r^{2}h

V = pi*(7.5)^2*22

V = 3887.72 ft^{3}

b) Volume of the tank in m^{3}:

We must convert both the radius and the height to m.

Each feet has 0.30 m, so:

Radius:

1 feet - 0.30m

7.5 feet - r m

r = 7.5*0.30

r = 2.25m

Height

1 feet - 0.30m

22f - h m

h = 22*0.30

r = 6.60m

The volume is:

V = \pi r^{2}h

V = pi*(2.25)^2*6.60

V = 104.97 m^{3}

c) Volume of the tank in cm^{3}:

Each m has 100 cm.

So r = 2.25m = 225cm

h = 6.60m = 660cm

The volume is:

V = \pi r^{2}h

V = pi*(225)^2*660

V = 104,968,468.538 cm^{3}

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