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3 years ago

Can someone pleaseee help me i’ll give you brainliest

Mathematics

1 answer:

mina [271]3 years ago

8 0

I think it’s the second option, hope this helps. If it’s correct please give brainliest

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Write an algebraic expression to find the AREA of a rectangle with a length of 4x-5 and a width of 7.

blagie [28]

Answer:

28x-35

Step-by-step explanation:

4x*7=28x

5*7=35

8 0

3 years ago

what number must be added to 3 and 8 so that the ratio of the first number to the second number is equal to 3 :4

Grace [21]

The answer is 12.
Steps
If that number is x
(3+x)/(8+x)=3/4
"Cross multply"
4(3+x)=3(8+x)
12+4x=24+3x
x=12
To check: add 12 to 3 and 8. 3+12=15 and 8+12=20. 15/20=3/4

3 0

3 years ago

- the following functions.

77julia77 [94]

Answer:

(f+g)(1)

equals

Step-by-step explanation:

(f+g)(1) is f(1)+g(1).

f(1) means what y corresponds to x=1 so f(1)=-1.

g(1) means what y corresponds to x=1 so g(1)=4.

So (f+g)(1)=f(1)+g(1)=-1+4=3.

4 0

3 years ago

...........................

9966 [12]

The answer to your question would be A

7 0

3 years ago

The vertices of a triangle ABC are A(7, 5), B(4, 2), and C(9, 2). What is measure of angle ABC? 30° 45° 56.31° 78.69°

GenaCL600 [577]

The measure of angle ABC is 45°

Explanation

Vertices of the triangle are: A(7, 5), B(4, 2), and C(9, 2)

According to the diagram below....

Length of the side BC (a) $=\sqrt{(4-9)^2+(2-2)^2}= \sqrt{25}= 5$

Length of the side AC (b) $= \sqrt{(7-9)^2 +(5-2)^2}= \sqrt{4+9}=\sqrt{13}$

Length of the side AB (c) $= \sqrt{(7-4)^2 +(5-2)^2} =\sqrt{9+9}=\sqrt{18}$

We need to find ∠ABC or ∠B . So using Cosine rule, we will get...

$cosB= \frac{a^2+c^2-b^2}{2ac} \\ \\ cos B= \frac{(5)^2+(\sqrt{18})^2-(\sqrt{13})^2}{2*5*\sqrt{18} }\\ \\ cosB= \frac{25+18-13}{10\sqrt{18}} =\frac{30}{10\sqrt{18}}=\frac{3}{\sqrt{18}}\\ \\ cosB=\frac{3}{3\sqrt{2}} =\frac{1}{\sqrt{2}}\\ \\ B= cos^-^1(\frac{1}{\sqrt{2}})= 45 degree$

So, the measure of angle ABC is 45°

7 0

3 years ago

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