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Brilliant_brown [7]
3 years ago
10

Help me with this please

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
7 0
The answer is b^5, as when terms with the same base are multiplied, their exponents are added together and (-6) + 11 = 5
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The inverse of it is the inverse of that & thing u know
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How do I simplify (6^-2)(3^-3)(3 x 6)^4? Not the answer, just the simplified expression.
Mazyrski [523]

The simplification form of the provided expression is 108 after applying the integer exponent properties.

<h3>What is integer exponent?</h3>

In mathematics, integer exponents are exponents that should be integers. It may be a positive or negative number. In this situation, the positive integer exponents determine the number of times the base number should be multiplied by itself.

We have an expression:

=\left(6^{-2}\right)\left(3^{-3}\right)\left(3\:\cdot \:6\right)^4

=\dfrac{1}{36}\cdot \dfrac{1}{27}\left(3\cdot \:6\right)^4

=\dfrac{1}{36}\cdot \dfrac{1}{27}\cdot \:81\cdot \:1296

=\dfrac{1}{36}\cdot \dfrac{1}{27}\cdot \dfrac{104976}{1}

=\dfrac{104976}{972}

= 108

Thus, the simplification form of the provided expression is 108 after applying the integer exponent properties.

Learn more about the integer exponent here:

brainly.com/question/4533599

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5 0
1 year ago
Please help! I will mark brainlest! HELP!? Please show steps also, thank you!
ddd [48]

Answer:

That's the question...?

Step-by-step explanation:

Girl I don't even think that's possible to answer.

4 0
2 years ago
What is one third plus one fourth and what is 1/3 + 1/2
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1/3+1/2=5/6
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X + 2y = 33<br> x-y = 11
Nostrana [21]

Answer:

x=\frac{55}{3},\:y=\frac{22}{3}

Step-by-step explanation:

Solve by Elimination

\begin{bmatrix}x+2y=33\\ x-y=11\end{bmatrix}

\begin{bmatrix}x+2y=33\\ -3y=-22\end{bmatrix}

-3y=-22

Divide -3 on both sides

y=\frac{22}{3}

x+2\cdot \frac{22}{3}=33

\mathrm{Subtract\:}2\frac{22}{3}\mathrm{\:from\:both\:sides}

x+2\cdot \frac{22}{3}-2\cdot \frac{22}{3}=33-2\cdot \frac{22}{3}

x=\frac{55}{3}

x=\frac{55}{3},\:y=\frac{22}{3}

6 0
3 years ago
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