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3 years ago

13

Sarah swam four-fifths of a lap in the morning and seven-fifteenths of a lap in the evening. How much farther did Sarah swim in

the morning than in the evening?

1 answer:

ryzh [129]3 years ago

8 0

1/3 is the answer
Hope this is correct

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Can someone please help me on this

wlad13 [49]

Answer:

15.7 inches

Step-by-step explanation:

A clock is a circle . It tells us that the radius of the circle is 2.5 inches, and it is asking for the circumference. Therefore, we can use the equations for a circle to solve for the circumference.

$Circumference=2\pi r\\C = 2 \pi (2.5)\\C = 15.708$

3 0

3 years ago

2 1/4(4x-1)=1 3/5(1+4x)?? I need help with this problem. Thanks!!

koban [17]

Solving $2\frac{1}{4}(4x-1)=1\frac{3}{5}(1+4x)$ we get $x=\frac{77}{52}$

Step-by-step explanation:

We need to solve the problem: $2\frac{1}{4}(4x-1)=1\frac{3}{5}(1+4x)$

Solving:

$2\frac{1}{4}(4x-1)=1\frac{3}{5}(1+4x)\\\frac{9}{4}(4x-1)=\frac{8}{5}(1+4x)\\9x-\frac{9}{4}=\frac{8}{5}+\frac{32x}{5}$

Add 9/4 on both sides:

$9x-\frac{9}{4}+\frac{9}{4}=\frac{8}{5}+\frac{32x}{5}+\frac{9}{4}$

$9x=\frac{8}{5}+\frac{9}{4}+\frac{32x}{5}\\9x-\frac{32x}{5}=\frac{8}{5}+\frac{9}{4}\\\frac{9x*5-32x}{5}=\frac{8*4+9*5}{20}\\\frac{45x-32x}{5}=\frac{32+45}{20}\\\frac{13x}{5}=\frac{77}{20}\\x=\frac{77}{20}\times \frac{5}{13}\\x=\frac{77}{4*13}\\x=\frac{77}{52}$

So, Solving $2\frac{1}{4}(4x-1)=1\frac{3}{5}(1+4x)$ we get $x=\frac{77}{52}$

Keywords: Solving Fractions

Learn more about Solving Fractions at:

#learnwithBrainly

8 0

4 years ago

Are two lines parallel, perpendicular or neither 3x+7y=15 and 7x-3y=6

maw [93]

Answer:

The lines are perpendicular

Step-by-step explanation:

we know that

If two lines are parallel, then their slopes are equal

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

we have

$3x+7y=15$ ----> equation A

isolate the variable y

$7y=-3x+15$

Divide by 7 both sides

$y=-\frac{3}{7}x+\frac{15}{7}$

The slope of the line A is $m_A=-\frac{3}{7}$

$7x-3y=6$ ----> equation B

isolate the variable y

$3y=7x-6$

Divide by 3 both sides

$y=\frac{7}{3}x-2$

The slope of the line B is $m_B=\frac{7}{3}$

Compare the slope of both lines

$m_A=-\frac{3}{7}$

$m_B=\frac{7}{3}$

so

$m_A \neq m_B$ ----> the lines are not parallel

Find the product of the slopes

$-\frac{3}{7}(\frac{7}{3})=-1$ ----> the lines are perpendicular

4 0

3 years ago

Simplify (10 x 10^5)/(2 x 10^-5)

dybincka [34]

The answer to the question

3 0

3 years ago

Juanita borrowed $600 to purchase a new computer. She was charged 7% interest for two years. How much interest will Juanita pay?

lions [1.4K]

Juanita will pay$ 558.00

7 0

4 years ago

Read 2 more answers