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OleMash [197]
3 years ago
10

Divide and write in simplest form.

Mathematics
1 answer:
iren2701 [21]3 years ago
4 0

Answer:

1. \frac{3}{17} (3/17)

2. \frac{3}{7} (3/7)

3.  \frac{45}{184} (45/184)

Step-by-step explanation:

1. \frac{\frac{3}{5} }{3\frac{2}{5}} = \frac{\frac{3}{5} }{\frac{17}{5}} = \frac{\frac{3}{1} }{\frac{17}{1}}= \frac{3}{17}

2. \frac{2}{4\frac{2}{3}} = \frac{\frac{2}{1} }{\frac{14}{3}}= \frac{2}{1} /\frac{14}{3} = \frac{2}{1} *\frac{3}{14} = \frac{6}{14} = \frac{3}{7}

3. \frac{\frac{5}{4} }{5\frac{1}{9} } = \frac{\frac{5}{4} }{\frac{46}{9}} = \frac{5}{4}/\frac{46}{9} = \frac{5}{2}/\frac{23}{9} = \frac{5}{2}*\frac{9}{23} = \frac{45}{184}

Hope this helps!

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Weird. A period appears above this... huh.

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Step-by-step explanation:

What the word problem really wants us to get [is ]the question of 'Which is greater, A=6a^2 when 'a' [is] 18 or A=4\pir^2 when r = 9? And here's how to solve that.

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