Answer:
15.625 grams
Step-by-step explanation:
The decay is First order reaction
The half life of the first order reaction is given by
T(1/2) = ㏑2/K
where K is the reaction constant for the first order reaction
T(1/2) = 2
2 = ln 2 /K
K = ln2/2
The equation of the first order reaction is given by
Kt = ln ()
where
t = time = 10years
Ro = initial concentration
R = amount left after time t
upon substituting the values
5ln2 = ln (500/R)
ln = ln (500/R) (a*lnb = ln
)
R = 500/32 = 15.625grams
Therefore the amount of pesticide left after 10 years is 15.625grams