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PIT_PIT [208]
3 years ago
9

How do I find an angle to a 90 degree triangle with only the length of the sides

Mathematics
1 answer:
atroni [7]3 years ago
3 0

Answer:

22.6°

Step-by-step explanation:

the cosines rule :

cos x = (24²+26²-10²)/2(24)(26)

= (576+676-100)/1248

= 1152/1248

= 0.923

so, x = cos`¹ 0.923 = 22.6°

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aalyn [17]
(y+1)=3(x-1) is the answer to your problem
4 0
3 years ago
the length of a rectangle is five feet less than its width. If the area of the rectangle is 84 square feet, find its dimensions
KIM [24]
Let
x---------> the length of the rectangle
y--------> the width of the rectangle

we know that
A=84 ft²
[area of rectangle]=x*y-----> 84=x*y-----> equation 1
x=y-5------> equation 2
substitute 2 in 1
84=[y-5]*y-----> 84=y²-5y---------> y²-5y-84=0

using a graph tool-----> to resolve the second order equation
see the attached figure

the solution is
y=12
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the answer is
the length of the rectangle is 7 ft
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6 0
3 years ago
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Murljashka [212]

Answer:

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4 0
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I think I know this much so far for A (but I could be wrong):
Eduardwww [97]
Part A. You have the correct first and second derivative.

---------------------------------------------------------------------

Part B. You'll need to be more specific. What I would do is show how the quantity (-2x+1)^4 is always nonnegative. This is because x^4 = (x^2)^2 is always nonnegative. So (-2x+1)^4 >= 0. The coefficient -10a is either positive or negative depending on the value of 'a'. If a > 0, then -10a is negative. Making h ' (x) negative. So in this case, h(x) is monotonically decreasing always. On the flip side, if a < 0, then h ' (x) is monotonically increasing as h ' (x) is positive.

-------------------------------------------------------------

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h  ' (x) = -10a(-2x+1)^4
0 = -10a(-2x+1)^4
so either
-10a = 0 or (-2x+1)^4 = 0
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Answer:

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