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Archy [21]
2 years ago
14

Un ingeniero realiza las siguientes observaciones sobre las ventas de impresoras en una tienda: Hay impresoras Epson, Hp y Canno

n. El número de impresoras Epson y HP es cinco veces el número de las Cannon. Además, el número de impresoras Epson es el triple que el de la Cannon y El total de impresoras Cannon y Hp asciende a 123​
Mathematics
1 answer:
Karolina [17]2 years ago
3 0

Answer:

En la tienda hay 123 impresoras Epson, 82 impresoras HP y 41 impresoras Cannon.

Step-by-step explanation:

Para determinar el número de impresoras de cada marca, se deben plantear las siguientes ecuaciones:

E + HP = 5 x C

E = 3 x C

C + HP = 123

Así, teniendo en cuenta estas ecuaciones y los valores de cada marca dentro del stock de la tienda, se puede plantear la siguiente equivalencia:

Si E = 3C y E + HP = 5C, entonces HP = 2C, ya que 5C - 3C = 2C.

Entonces, las equivalencias son las siguientes:

E = 3C

HP = 2C

Si C + HP = 123, podríamos decir que 3C = 123. Por ello, dado que 123 / 3 es igual a 41, el número de impresoras Cannon asciende a 41 unidades.

A su vez, el número de impresoras HP es de 82 unidades (41 x 2), mientras que el número de impresoras Epson asciende a 123 unidades (41 x 3).

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Y = 2 - 2
Hunter-Best [27]

Answer:

B. No

Step-by-step explanation:

In order to see if (4, 2) is a solution, we have to plug 4 in for x and 2 in for y in the equations. If it's a true statement, then we know that the point is a solution.

One of the equations is y = 3x + 4. Plug in 4 for x and 2 for y:

y =? 3x + 4

2 =? 3 * 4 + 4

2 =? 12 + 4

2 ≠ 16

Thus, we know that (4, 2) is not a solution and the answer is B.

<em>~ an aesthetics lover</em>

6 0
3 years ago
Let us denote by P the set of all people, by S the set of people who are single, by C the set of people who have children, by W
natita [175]

Solution :

Given :

The events are as follows :

P : Set of all the people

S : Set of people those who are single

C : Set of people having children

W : Set of women

M : Set of men

a). Now set of married women having children is given by :

$\left( (P-S)-M \right) \cap C $

And set of single women who do not have any children : (S -C) - M

Thus the set of women those who are either married and have children or they are single and they do not have any children is represented by :

$\left( (S-C)-M\right) \cup \left( ((P-S)-M) \cap C \right) $

b). Set of Married men : $\left( (P-S) \cap M$

   Set of Married men : $\left( (P-S) \cap W$

   Set of all possible married who are heterosexual couples, that is, all possible pairings of the married men and the married women is represented by :

   $((P-S) \cap M) \cap ((P-S) \cap W )$

c). The number of all the possible married heterosexual couples will be represented by the cardinality of the above set, which represents the number of the elements in the set.

Thus the number of the married heterosexual couples is given by :

$n[((P-S) \cap M) \cap ((P-S) \cap W)]$

8 0
3 years ago
Help me pleaseeeeeeeeeeeeeeeee
zalisa [80]

Step-by-step explanation:

j=25+5

j=30

final answer is 30

3 0
3 years ago
Read 2 more answers
Mrs. Blanda's truck holds 19.7 gallons of gas. She used 4 full tanks fo gas last month and paid $3 for each gallon. How much did
Yakvenalex [24]

Answer:

$236.40

Step-by-step explanation:

Mrs. Blanda's truck holds 19.7 gallons of gas. She used 4 full tanks of gas last month.

1 full tank  holds 19.7 gallons of gas

4 full tank hold 4*19.7 gallons of gas

4 full tank = 78.8 gallons of gas used last month

She paid $3 for each gallon

We need to find the amount she paid for 78.8 gallons

78.8 * 3= 236.4

Mrs. Blanda spend on gas last month = $236.40

8 0
3 years ago
Write the explicit formula for the geometric sequence.
saw5 [17]
Ur answer is c to ur question
8 0
3 years ago
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