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2 years ago

Find the difference: 1 0.4 3 0 8

Mathematics

1 answer:

Dima020 [189]2 years ago

4 0

Answer:

0.5692

Step-by-step explanation:

1 - MINUS 0.4308 = EQUALS 0.5692 BUT I DONT THAT IS IT

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Add the complex numbers. (-2-4i)+(-12+7i) = ??

lions [1.4K]

Question:

(-2 - 4i) + (-12 + 7i)

= -14 + 3i

6 0

2 years ago

Read 2 more answers

0.9 as a simplified ratio

Bas_tet [7]

All numbers that are 0._ are _/10 therefore that would be 9/10 because this ratio cannot be simplified further.

3 0

3 years ago

PLEASE HELP ME! Drag the expressions into the boxes to correctly complete the table.

Kamila [148]

The polynomials are:

$x^4+3x^3-5x^2-7x+20$

$x^3-2x^2+x-12$

$x^2+3x^5-6x+12x^3$

Not a polynomial are:

$4\sqrt[3]{x} -\sqrt{x} -20$

$\frac{5}{x^3}-\frac{1}{x^2}+\frac{8}{x}-40$

$x^{-3}-x^{-2}-6x^{-1}+8$

Solution:

Polynomial is an expression with variables and coefficients,

Which involves only the operations of addition, subtraction, multiplication, and non-negative integer exponents of variables

Option 1

$4\sqrt[3]{x} -\sqrt{x} -20$

Polynomial does not include roots

This is not a polynomial equation

Option 2

$x^4+3x^3-5x^2-7x+20$

This is polynomial expression involving addition and subtraction between terms with non-negative integer exponents of variables

Option 3

$\frac{5}{x^3}-\frac{1}{x^2}+\frac{8}{x}-40$

This is not a polynomial. This equations involves negative integer exponents of variables

Option 4

$x^3-2x^2+x-12$

This is a polynomial involving addition and subtraction between terms with non-negative integer exponents of variables

Option 5

$x^{-3}-x^{-2}-6x^{-1}+8$

This is not a polynomial. This equations involves negative integer exponents of variables

Option 6

$x^2+3x^5-6x+12x^3$

This is a polynomial involving addition and subtraction between terms with non-negative integer exponents of variables

5 0

3 years ago

a train travels 288km at a uniform speed.if the speed has been 4km per hour more it would have taken one hour less for the same

Lostsunrise [7]

Given:

A train travels 288 km at a uniform speed.

If the speed has been 4 km per hour more it would have taken one hour less for the same journey.

To find:

The initial speed of the train.

Solution:

Let x km/h be the initial speed on the train.

New speed of train = (x+4) km/h

We know that,

$Time=\dfrac{Distance}{Speed}$

Time taken by the train initially to cover 288 km is $\dfrac{288}{x}$ hours.

New time taken by the train to cover 288 km is $\dfrac{288}{x+4}$ hours.

It is given that If the speed has been 4 km per hour more it would have taken one hour less for the same journey.

$\dfrac{288}{x}-\dfrac{288}{x+4}=1$

$\dfrac{288(x+4)-288x}{x(x+4)}=1$

$288x+1152-288x=x^2+4x$

$1152=x^2+4x$

$0=x^2+4x-1152$

Splitting the middle term, we get

$x^2+36x-32x-1152=0$

$x(x+36)-32(x+36)=0$

$(x+36)(x-32)=0$

$x=-36,32$

We know that the speed cannot be negative. So, the only possible value of x is 32.

Therefore, the speed of the train is 32 km/h.

3 0

2 years ago

PLEASE!!!!!!!!!!!!!!!!!!!!THIS IS DUE TODAY

rjkz [21]

3 + 1.75m

This represents 1.75 per mile plus a one time 3 charge.

Another way this can be written is

(1.75m + 6) - 3

This is a less efficient way, but represents the same. It is 1.75 per mile, this is plus 6, therefore we add the -3 outside the parenthesis so it evens out to +3 as the base charge.

Example: Lets say its 3 miles.

3 + 1.75 (3) = 8.25

(1.75 (3) + 6) - 3 = 8.25

6 0

3 years ago

Read 2 more answers