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3 years ago

What are the answers to these questions?

Mathematics

1 answer:

Ludmilka [50]3 years ago

3 0

A foot is 12 inches.
An inch is 1/12 of a foot.
To convert feet to inches, multiply the feet by 12.
To convert inches to feet, divide the inches by 12.
3.) In my table, the inches would change to centimeters and be 100. The feet would change to meters and be 1.
4.) Make a table like the one at the top except with centimeters and meters. You have to do this on your own.

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1. Write the equation for the function graphed<br> below.<br> -10<br> -5<br> 10

Vsevolod [243]

There is no illustration, so it is impossible to answer this question. I apologise.

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3 years ago

How do you find the slope of ordered pairs

DerKrebs [107]

Answer:

the slope is defined as the change in price divided by the change in quantity supplied between two points (i.e. the two ordered pairs). we can use the following formula to calculate it: m = (y2 – y1)/(x2 – x1). in the case of my example, the two ordered pairs are (2, 500) and (1, 250)

Step-by-step explanation:

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3 years ago

Convert 1/2 yard in inches

Tom [10]

1/2 yard =18 inches

(multiply value by 36)

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3 years ago

(-4)(5)+(-3)(-2) whats is it???

Vlada [557]

Answer:

-14

Step-by-step explanation:

(-4)(5)+(-3)(-2)

=-20+6

=-14

5 0

4 years ago

Read 2 more answers

Solve the equation by graphing. If exact roots cannot be found, state the consecutive integers between which the roots are locat

zavuch27 [327]

Answer:

The equation contains exact roots at x = -4 and x = -1.

See attached image for the graph.

Step-by-step explanation:

We start by noticing that the expression on the left of the equal sign is a quadratic with leading term $x^2$ , which means that its graph shows branches going up. Therefore:

1) if its vertex is ON the x axis, there would be one solution (root) to the equation.

2) if its vertex is below the x-axis, it is forced to cross it at two locations, giving then two real solutions (roots) to the equation.

3) if its vertex is above the x-axis, it will not have real solutions (roots) but only non-real ones.

So we proceed to examine the vertex's location, which is also a great way to decide on which set of points to use in order to plot its graph efficiently:

We recall that the x-position of the vertex for a quadratic function of the form $f(x)=ax^2+bx+c$ is given by the expression: $x_v=\frac{-b}{2a}$

Since in our case $a=1$ and $b=5$ , we get that the x-position of the vertex is: $x_v=\frac{-b}{2a} \\x_v=\frac{-5}{2(1)}\\x_v=-\frac{5}{2}$

Now we can find the y-value of the vertex by evaluating this quadratic expression for x = -5/2:

$y_v=f(-\frac{5}{2})\\y_v=(-\frac{5}{2} )^2+5(-\frac{5}{2} )+4\\y_v=\frac{25}{4} -\frac{25}{2} +4\\\\y_v=\frac{25}{4} -\frac{50}{4}+\frac{16}{4} \\y_v=-\frac{9}{4}$

This is a negative value, which points us to the case in which there must be two real solutions to the equation (two x-axis crossings of the parabola's branches).

We can now continue plotting different parabola's points, by selecting x-values to the right and to the left of the $x_v=-\frac{5}{2}$ . Like for example x = -2 and x = -1 (moving towards the right) , and x = -3 and x = -4 (moving towards the left.

When evaluating the function at these points, we notice that two of them render zero (which indicates they are the actual roots of the equation):

$f(-1) = (-1)^2+5(-1)+4= 1-5+4 = 0\\f(-4)=(-4)^2+5(-4)_4=16-20+4=0$

The actual graph we can complete with this info is shown in the image attached, where the actual roots (x-axis crossings) are pictured in red.

Then, the two roots are: x = -1 and x = -4.

5 0

3 years ago