17 out of 25 in a decimal
2 answers:
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Answer:
Richard's cumulative GPA = 2.5
Step-by-step explanation:
Richard's cumulative GPA for 3 semesters was 2.0 for 42 credits.
Average = 2
Total credits = 42
Average = sum of terms/total no of terms
2 = sum of terms/42
sum of terms = 84 ....(1)
His fourth semester GPA was 4.0 for 14 course units
Average = 4
Total credits = 14
sum of terms = 56 .....(2)
Average for 4 semesters,
Hence, Richard's cumulative GPA for all 4 semesters is 2.5.
Slope = (y2 - y1)/(x2 - x1) = (1 - 3)/(-2 - (-5)) = -2/(-2 + 5) = -2/3
For perpendicular lines, m2 = -1/m1 = -1/(3/8) = -8/3
A line passing through point (-4, 0) and parallel to the y-axis is x = -4
radius = diameter/2 = 10/2 = 5
center of circle = midpoint of diameter = ((-3 + 5)/2, (1 + 7)/2) = (2/2, 8/2) = (1, 4)
Required equation is (x - 1)^2 + (y - 4)^2 = 5^2
(x - 1)^2 + (y - 4)^2 = 25
For perpendicular lines, m2 = -1/m1 = -1/(3/8) = -8/3
A line passing through point (-4, 0) and parallel to the y-axis is x = -4
radius = diameter/2 = 10/2 = 5
center of circle = midpoint of diameter = ((-3 + 5)/2, (1 + 7)/2) = (2/2, 8/2) = (1, 4)
Required equation is (x - 1)^2 + (y - 4)^2 = 5^2
(x - 1)^2 + (y - 4)^2 = 25