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Olin [163]
3 years ago
9

CAN SOMEONE PLEASE PLEASE HELP ME ON THIS IM DESPERATE

Mathematics
1 answer:
storchak [24]3 years ago
5 0

Answer:

The angle has a measure of \frac{5\pi}{6} radians.

Step-by-step explanation:

According to the statement, an angle centered at the center of the circle covers an arc of \frac{25\pi}{6} units, the arc is a portion of the circunference. We include a figure representing the circle below.

Where:

R - Radius, measured in units.

s - Arc, measured in units.

\alpha - Angle of the arc, measured in radians.

From Geometry, we can calculate the length of the arc by means of this equation:

s = \alpha\cdot R (1)

If we know that R = 5 and s = \frac{25\pi}{6}, then the angle of the arc is:

\alpha = \frac{s}{R}

\alpha = \frac{\frac{25\pi}{6} }{5}

\alpha = \frac{25\pi}{30}

\alpha = \frac{5\pi}{6}\,rad

The angle has a measure of \frac{5\pi}{6} radians.

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Solve the following equation. Remember to check for extraneous solutions 1/(x-6) + (x/(x-2)) = (4/(x²-8x+12)).
xxMikexx [17]

Answer:

-1, 2, 6

Step-by-step explanation:

We have to solve the equation as follows: 1/(x-6) + (x/(x-2)) = (4/(x²-8x+12)).

Now, we have, \frac{1}{x-6} +\frac{x}{x-2} = \frac{4}{x^{2}-8x+12 }

⇒\frac{(x-2)+x(x-6)}{(x-2)(x-6)} = \frac{4}{x^{2}-8x+12 }

⇒\frac{x-2+x^{2}-6x }{(x-2)(x-6)} =\frac{4}{(x-2)(x-6)}

⇒\frac{(x-2)(x-6)}{x^{2}-5x-2 }=\frac{(x-2)(x-6)}{4}

⇒(x-2)(x-6)[\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0

⇒ (x-2)(x-6) =0 or, [\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0

If, (x-2)(x-6) =0, then x=2 or x=6

If, [\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0, then x^{2} -5x-2=4

and (x-6)(x+1) =0

Therefore, x=6 or -1

So the solutions for x are -1, 2 6. (Answer)

4 0
4 years ago
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