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baherus [9]
3 years ago
5

Just check if these answers are right please.. Seriously check them one answer by another...

Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
6 0
4a) $1.4/pound - correct
4b) $8.4 - correct
4c) 15 pounds - correct
4d and e) look correct
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A university is applying classification methods in order to identify alumni who may be interested in donating money. The univers
HACTEHA [7]

The accuracy in the research done by university is 0.81, sensitivity is 0.93, specificity is 0.81 and precision is 0.047.

Given sample size of 58205 and proportion of people donated 576. Cutoff is 0.5.

Probability is the chance of happening an event among all the events possible. It lies between 0 and 1.

TP=total people donated in sample, TN=total number of people,FP=donation,FN=No donation

Accuracy is calculated as under:

=(TP+TN)/(TP+TN+FP+FN)

=(268+23439)/(238+23439+5375+20)

=23707/29102

=0.81

Accuracy=0.81

Sensitivity is calculated as under:

=TP/(TP+FN)

=268/(268+20)

=268/288

=0.93

Precision is calculated as under:

=TP/(TP+FP)

=268/(268+5375)

=268/5643

=0.047

Their values are the probabilities in itself.

Hence accuracy is 0.81, sensitivity is 0.93, specificity is 0.81 and precision is 0.047.

Learn more about probability at brainly.com/question/24756209

#SPJ4

7 0
2 years ago
What is the inverse function of y = √ x − 1 2 , x ≥ 1 2a. y=x2−14,x≥0 b. y=x2−12,x≥0 c. y=x2+12,x≥0 d. y=x2+14,x≥0
hammer [34]

The function is :

y = √(x-12), x≥12


To find the inverse function, we interchange x and y, and then make y the subject again.


So interchanging x and y we have:


x = √(y-12)


Squaring both sides gives;

x² = y-12



Now making y the subject we have,


y = x² +12

x≥0.


Therefore the inverse function is;

y = x² +12, x≥0.


Hence the correct answer is C.



7 0
4 years ago
Which ordered pair represents a reflection of the point (- 3, 5) across the yaxis?
GREYUIT [131]

Answer:

3/5

Step-by-step explanation:

Reflecting on the y axis means changing the x coordinate changes to it's opposite.

6 0
3 years ago
Explain how the Associative Property can be used to mentally find the volume of the prisms shown
Leona [35]
<h2>Answer:</h2>

A prism is a solid object having two identical bases, hence the same cross section along the length. This is a rectangular prism its base is a rectangle. multiplying the three dimensions of a rectangular prism: length, width and height, gives us the volume of a prism:

V=L\times W\times H

Therefore, Associative Property can be used to mentally find the volume of the prisms shown by selecting the easier way of the multiplication. For instance, we can say that:

L=5cm \\ \\ W=18cm \\ \\ H=20cm

In whose case:

V=5\times 18\times 20

To operate this mentally is not an easy way, but<em> what if we rotate this shape? </em>so we say that:

L=18cm \\ \\ W=20cm \\ \\ H=5cm

Then, the volume can be found as:

V=18\times 20\times 5

There are two forms of finding the result. First, multiplying 18 by 20 and then the result by 5, but as in the previous case this is a tricky way to do mentally:

V=(18\times 20)\times 5

Hence, here we can use Associative Property multiplying 20 by 5 and then the result by 18:

V=18\times (20\times 5)

This last arrangement is easier because 20 x 5 is easy to remember given that the result is 100. Then, by multiplying this result by 18 then we get 1800.

3 0
3 years ago
The volume of two spheres are 327\pi in^{3} and 8829\pi in^{3}
Crazy boy [7]
A dimension of a sphere is its radius, so it correlates with its volume, thus

\bf \qquad \qquad \textit{ratio relations}&#10;\\\\&#10;\begin{array}{ccccllll}&#10;&\stackrel{ratio~of~the}{Sides}&\stackrel{ratio~of~the}{Areas}&\stackrel{ratio~of~the}{Volumes}\\&#10;&-----&-----&-----\\&#10;\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}&#10;\end{array}\\\\&#10;-----------------------------

\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\&#10;-------------------------------\\\\&#10;%The volume of two spheres are 327\pi in^{3} and 8829\pi in^{3}&#10;\cfrac{small}{large}\qquad \cfrac{s}{s}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\implies \cfrac{s}{s}=\cfrac{\sqrt[3]{327}}{\sqrt[3]{8829}}\qquad &#10;\begin{cases}&#10;8829=3\cdot 3\cdot 3\cdot 327\\&#10;\qquad 3^3\cdot 327&#10;\end{cases}

\bf \cfrac{s}{s}=\cfrac{\sqrt[3]{327}}{\sqrt[3]{3^3\cdot 327}}\implies \cfrac{s}{s}=\cfrac{\underline{\sqrt[3]{327}}}{3\underline{\sqrt[3]{327}}}\implies \cfrac{s}{s}=\cfrac{1}{3}
6 0
3 years ago
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