Answer:
#1 - All real numbers are solutions.
#2 - All real numbers are solutions.
Step-by-step explanation:
#1 -
Let's solve your equation step-by-step.
12(6t−4)=3t−2
Step 1: Simplify both sides of the equation.
12(6t−4)=3t−2
(12)(6t)+(12)(−4)=3t+−2(Distribute)
3t+−2=3t+−2
3t−2=3t−2
Step 2: Subtract 3t from both sides.
3t−2−3t=3t−2−3t
−2=−2
Step 3: Add 2 to both sides.
−2+2=−2+2
0=0
Same for #2
Answer:
x = -2 + 2 i or x = -2 - 2 i
Step-by-step explanation:
Solve for x:
x^2 + 4 x + 8 = 0
Subtract 8 from both sides:
x^2 + 4 x = -8
Add 4 to both sides:
x^2 + 4 x + 4 = -4
Write the left hand side as a square:
(x + 2)^2 = -4
Take the square root of both sides:
x + 2 = 2 i or x + 2 = -2 i
Subtract 2 from both sides:
x = -2 + 2 i or x + 2 = -2 i
Subtract 2 from both sides:
Answer: x = -2 + 2 i or x = -2 - 2 i
Answer:
0.70275
Step-by-step explanation:
Data provided in the question:
4e²ˣ⁻¹ -1 = 5
now solving for 'x'
⇒ 4e²ˣ⁻¹ = 5 + 1
or
⇒ 4e²ˣ⁻¹ = 6
or
⇒ 
or
⇒ 
now,
taking natural log both sides, we get
⇒ 2x - 1 = 
also,
we know
⇒ 
thus,
⇒ 2x - 1 = ln(3) - ln(2)
or
⇒ 2x - 1 = 1.0986 - 0.6931
or
⇒ 2x - 1 = 0.4055
or
⇒ 2x = 0.4055 + 1
or
⇒ 2x = 1.4055
or
⇒ x = 0.70275
It can't be a whole number. It can be 1.5, or 1 1/2.
