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2 years ago

Consider the rectangle enlargement. Pls answer the three questions I will mark brainliest!!

Mathematics

1 answer:

Alenkasestr [34]2 years ago

7 0

Answer:

Perimeter of the original Rectangle is

2(4.5+4.3)=2×8.8= 17.6 mm

Side length of the enlarged rectangle is

$\frac{4.5}{4.3} = \frac{24.3}{x} \\ x = \frac{24.3 \times 4.3}{4.5} \\ \boxed{x = 23.22 \: mm}$

Perimeter of the enlarged rectangle

2(24.3+23.22)= 2×47.52= 95.04 mm

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Which quadrant will the line y=Negative one-fourthx – 15 never pass through?

Nata [24]

Answer:

quadrant 2

Step-by-step explanation:

6 0

2 years ago

At what point does the curve have maximum curvature? Y = 4ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as

MAXImum [283]

Answer-

At $x= \frac{1}{2304e^4-16e^2}$ the curve has maximum curvature.

Solution-

The formula for curvature =

$K(x)=\frac{{y}''}{(1+({y}')^2)^{\frac{3}{2}}}$

Here,

$y=4e^{x}$

Then,

${y}' = 4e^{x} \ and \ {y}''=4e^{x}$

Putting the values,

$K(x)=\frac{{4e^{x}}}{(1+(4e^{x})^2)^{\frac{3}{2}}} = \frac{{4e^{x}}}{(1+16e^{2x})^{\frac{3}{2}}}$

Now, in order to get the max curvature value, we have to calculate the first derivative of this function and then to get where its value is max, we have to equate it to 0.

${k}'(x) = \frac{(1+16e^{2x})^{\frac{3}{2} } (4e^{x})-(4e^{x})(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})}{(1+16e^{2x} )^{2}}$

Now, equating this to 0

$(1+16e^{2x})^{\frac{3}{2} } (4e^{x})-(4e^{x})(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x}) =0$

$\Rightarrow (1+16e^{2x})^{\frac{3}{2}}-(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})$

$\Rightarrow (1+16e^{2x})^{\frac{3}{2}}=(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})$

$\Rightarrow (1+16e^{2x})^{\frac{1}{2}}=48e^{2x}$

$\Rightarrow (1+16e^{2x})}=48^2e^{2x}=2304e^{2x}$

$\Rightarrow 2304e^{2x}-16e^{2x}-1=0$

Solving this eq,

we get $x= \frac{1}{2304e^4-16e^2}$

∴ At $x= \frac{1}{2304e^4-16e^2}$ the curvature is maximum.

6 0

2 years ago

(06.06 MC) The work of a student to find the dimensions of a rectangle of area 8 + 12x and width 4 is shown below:

zheka24 [161]

Answer:

step 2

Step-by-step explanation:

theres a one in front of the () meaning it should have look like this

4+4x+2

7 0

2 years ago

(5-5)^2 - (6-5)^3 simplify the expression PLEASE HELP

leonid [27]

Answer: 15

Step-by-step explanation:

(5-1)^2 - (6-5)^3

(4)^2 - (1)^3

16-1

=15

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2 years ago

Read 2 more answers

6x square +11x-10 Factories

vova2212 [387]

Answer:

(2x+5)(3x-2)

Step-by-step explanation:

6x²+11x-10

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7 0

2 years ago