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3 years ago

13

Your local grocery has your favorite juice on sale buy one, get one half off. each carton costs $3.20. how many can you buy for

$20? write a java program to do tha

1 answer:

quester [9]3 years ago

4 0

3.20 ÷ 2 = 1.6
3.20 + 1.6 = 4.8 (2 for $4.8)
4.8 x 8 = $19.20
The answer should be 8

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Ingrid is going to see a movie. The movie is 106 minutes long. It takes Ingrid x minutes to get to the movie theater and the sam

Delicious77 [7]

The right answer is Option B.

Step-by-step explanation:

Given,

Length of movie = 106 minutes

Time taken to get to theater = x minutes

Time taken to get back = x minutes

Total time = x+x = 2x minutes

Total time = 154 minutes

According to given statement;

Time taken to get to and get back + Length of movie = Total time

2x+106=154

154=2x+106

The equation 154=2x+106 describes the time it takes Ingrid to get to the movie theater.

The right answer is Option B.

Keywords: equation, addition

Learn more about addition at:

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5 0

4 years ago

MAJJJOORR HELLPPPP!!!!!

Effectus [21]

The correct answer is:

X=2

Y=4

Here's how you solve it!

$log5\sqrt{5}( 125)= x$

Write in exponential form.

$log_{5} \frac{3}{2} 125=x$

$log_{5} \frac{3}{2} (5^{3} )=x$

Simplify.

x=2

$log_{2\sqrt{2}$ 64= y

Write in exponential form

$log_{2}\frac{3}{2} (2x^{6} )= y$

Simplify.

y=4

Hope this helps! :3

4 0

4 years ago

Charlie is a car salesman he earns $800 plus a 9% commission on all of her sales for the week if charlie receive the payment for

Westkost [7]

800+ (1960•.09) = 800+176.4=$976.40

3 0

3 years ago

Express 3.72727272727... as a rational number, in the form pq

Aloiza [94]

Hi there!

Let x = 3. 72727.... ---(i)

Multiply 100 in eqn. (i)

100x = 372. 72727... ---(ii)

Subtract Eqn. (i) from (ii)

100x - x = 372. 7272... - 3. 7272...

99x = 369

x = $\dfrac {369}{99}$

x = $\dfrac {41}{11}$

Hence, $\dfrac {41}{11}$ is th' required p-q form.

~ Hope it helps!

6 0

3 years ago

Find an equation of the line that passes through the points (-5, -3) and (3, 1)

Mkey [24]

$\bf (\stackrel{x_1}{-5}~,~\stackrel{y_1}{-3})\quad (\stackrel{x_2}{3}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{(-3)}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{(-5)}}}\implies \cfrac{1+3}{3+5}\implies \cfrac{4}{8}\implies \cfrac{1}{2}$

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{\cfrac{1}{2}}[x-\stackrel{x_1}{(-5)}]\implies y+3=\cfrac{1}{2}(x+5) \\\\\\ y+3=\cfrac{1}{2}x+\cfrac{5}{2}\implies y=\cfrac{1}{2}x+\cfrac{5}{2}-3\implies y = \cfrac{1}{2}x-\cfrac{1}{2}$

6 0

4 years ago

Read 2 more answers