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3 years ago

If the area of your garden is ( d^2 -16 ) and the length is (d+4

Mathematics

1 answer:

Alex17521 [72]3 years ago

5 0

Answer:

d^3+4d^2-16d-64

Step-by-step explanation:

d^d+d^2*4+(-16)d+(-16)*4

d^2d+4d^2-16d-16*4

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Betty's grade in science class is affected by the number of missing assignments. The table below shows the science grade percent

Angelina_Jolie [31]

Hi!

$y=-5x+95$

Plug in $15$ for $x$

$y=-5(15)+95$

Multiply $-5$ and $15$

$y=-75+95$

Add $-75$ and $95$

$y =15$

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Betty's percentage is 15%.

The rate of change is the amount it changes for every missing assignment, therefore it would be -5.

5 0

2 years ago

Solve the problem: -5-7=

SOVA2 [1]

Answer:

-12

Step-by-step explanation:

-5 7 = -12

4 0

3 years ago

Read 2 more answers

The vertices of quadrilateral MNPQ are M(−3,−2),N(−1,4),P(2,4), and Q(4,−2). Translate quadrilateral MNPQ using the vector ⟨3,−4

timofeeve [1]

Answer:

M'(0,-6),N'(2,0),P'(5,0) and Q'(7,-6)

Step-by-step explanation:

We are given that the vertices of quadrilateral MNPQ are M(-3,-2),N(-1,4),P(2,4) and Q(4,-2).

We have to translate the quadrilateral MNPQ using vector <3,-4>

The translate the coordinates of vertices (x,y) using the vector <a,b> is given by the rule

$(x,y)\rightarrow (x+a,y+b)$

Using the rule

The new coordinates of M

$(-3,-2)\rightarrow (-3+3,-4-2)$

$(-3,-2)\rightarrow (0,-6)$

The new coordinates of N

$(-1,4)\rightarrow (2,0)$

The new coordinates of P

$(2,4)\rightarrow (5,0)$

The new coordinates of Q

$(4,-2)\rightarrow (7,-6)$

Hence, after translation the new vertices of quadrilateral are

M'(0,-6),N'(2,0),P'(5,0) and Q'(7,-6)

5 0

3 years ago

Find the length of BC. Explain how you got it, please! Thanks!

Vinvika [58]

Answer:

BC = 30.73

Here,

$\sf \frac{AB}{BQ} = \frac{CD}{DQ}$

so first solve for QD

$\sf \hookrightarrow \frac{32}{15} = \frac{19.2}{DQ}$

$\sf \hookrightarrow 32(DQ)} =19.2(15)$

$\sf \hookrightarrow 32(DQ)} =288$

$\sf \hookrightarrow DQ =9$

Hence, QD = 9

Now! using Pythagoras theorem,

CD² + BD² = BC²

19.2² + (9+15)² = BC²

BC = √368.64+576

BC = 30.73499634

BC = 30.73 ( rounded to nearest hundredth )

4 0

2 years ago

Read 2 more answers

What is y > 2x - 4 and 6x +3y < 9

fgiga [73]

you can make a table of values using any intergers and as many as you need in this case I chose 0,1,2 then you replace them in your actual equation and find the values of y.finally plot.

after plotting the points you shade the unwanted region(the sign will direct you) in this case the wanted region is y>.so you shade the less than area.

for the second one you make the equation simpler

6x+3y<9

3y<-6x+9

and also make a table of values,replace were there's x and plot

I hope this helps!

for further questions please feel free to ask

4 0

2 years ago