If the area of your garden is ( d^2 -16 ) and the length is (d+4

Mathematics

1 answer:

Alex17521 [72]3 years ago

5 0

Answer:

d^3+4d^2-16d-64

Step-by-step explanation:

d^d+d^2*4+(-16)d+(-16)*4

d^2d+4d^2-16d-16*4

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The area of a trapezoid is 60 square inches. One of the bases is 8 inches long. The height is 6 inches long. What is the length

Mashcka [7]

Answer:

12 in

Step-by-step explanation:

The area (A) of a trapezoid is calculated as

A = $\frac{1}{2}$ h(b₁ + b₂ )

where h is the height and b₁, b₂ the parallel bases

Given h = 6, b₁ = 8 and A = 60 , then

$\frac{1}{2}$ × 6 × (8 + b₂ ) = 60 , that is

3(8 + b₂ ) = 60 ( divide both sides by 3 )

8 + b₂ = 20 ( subtract 8 from both sides )

b₂ = 12

The length of the second base is 12 inches

6 0

3 years ago

The sum of two numbers is 32. The difference between the numbers is 8. Write a system of equations to represent this situation.

zalisa [80]

$Let\: x,y\: (x>y>0) \: be \: the \: two \: numbers.\\We \: have \: an \: equality:\\\begin{cases} x + y = 32\\x - y = 8 \end{cases}\\ \Leftrightarrow \begin{cases} 2x = 40\\y = x - 8 \end{cases} \\ \Leftrightarrow \begin{cases} x = 20\\y = 20 - 8 = 12 \end{cases} \\ \Rightarrow The \: two \: numbers \: are \: 2 0 \: and \: 12$

7 0

3 years ago

How much times dose 9 go into 125???

lesya692 [45]

$125:9=\frac{125}{9}=\frac{90+36-1}{9}=\frac{90}{9}+\frac{36}{9}-\frac{1}{9}=10+4-\frac{1}{9}=14-\frac{1}{9}\\\\=13\frac{8}{9}\approx14\\\\Answer:\ 9\ go\ into\ 125:\ 13\frac{8}{9}\ times,\ approximate\ to\ 14$