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4 years ago

Someone please help I'm so stuck

Mathematics

1 answer:

Trava [24]4 years ago

7 0

The picture won't load, but I would surely help!

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in 2001, the population in a town was 12% more than it was in 2000. if the population was 25,160 in 2002, which is 10% more than

blagie [28]

2002=25,160
2001=22,644
2000=19,926.72 (need to round to 19,926)
2001:
25,160/10=2516
25,160-2516

2000:
22,644/10=2,264.4 (10%)
2,264.4/5=452.88 (2%)
2,264.4+452.88=2717.28 (12%)
22,644-2717.28=19.926.72

3 0

3 years ago

Easy question. Get your points for the day along with brainliest (15 more points) !

lawyer [7]

Answer:

its c......................................................

Step-by-step explanation:

5 0

3 years ago

A pair of parallel lines is cut by a transversal. One of the angles formed measures 58°.

Trava [24]

There are three more angles with the same measure. A pair of corresponding angles and a pair of vertical angles.

6 0

4 years ago

Read 2 more answers

For the month of October Lisa plan to go running every fifth day and walk every sixth day. If she begins on October 1, on what d

Tomtit [17]

Answer:

October 30 is the day of the month she will run and walk during the same day.

Step-by-step explanation:

To determine what day of the month will she run and walk during the same day, we will list the days she plans to go running and the days she plans to walk.

From the question, Lisa plan to go running every fifth day and walk every sixth day, then

If she begins on October 1, the days she will run will be

October 5, October 10, October 15, October 20, October 25, and October 30;

while the days she will walk will be

October 6, October 12, October 18, October 24, and October 30.

Since October 30 occurred among the days she will run and walk, then October 30 is the day of the month she will run and walk during the same day.

4 0

4 years ago

Need help please help me

ANTONII [103]

Megan:
x to the one third power = $x ^{1/3}$
x to the one twelfth power = $x ^{1/12}$

The quantity of x to the one third power, over x to the one twelfth power is:
 $\frac{x ^{1/3}}{x ^{1/12}}$

Since $\frac{ x^{a} }{ x^{b} } = x ^{a-b}$
then $\frac{x ^{1/3}}{x ^{1/12}} = x^{1/3-1/12}$

Now, just subtract exponents:
1/3 - 1/12 = 4/12 - 1/12 = 3/12 = 1/4

$\frac{x ^{1/3}}{x ^{1/12}} = x^{1/3-1/12} = x^{1/4}$

Julie:
x times x to the second times x to the fifth = x * x² * x⁵

The thirty second root of the quantity of x times x to the second times x to the fifth is
 $\sqrt[32]{x* x^{2} * x^{5} }$

Since $x^{a}* x^{b}= x^{a+b}$
Then $\sqrt[32]{x* x^{2} * x^{5} }= \sqrt[32]{ x^{1+2+5} } =\sqrt[32]{ x^{8} }$

Since $\sqrt[n]{x^{m}} = x^{m/n} }$
Then $\sqrt[32]{ x^{8} }= x^{8/32} = x^{1/4}$

Since both Megan and Julie got the same result, it can be concluded that their expressions are equivalent.

3 0

3 years ago