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3 years ago

Let p(x) = 7x + 5 and r(x) = x - 1. Find and evaluate (r x p) (5)

Mathematics

1 answer:

quester [9]3 years ago

8 0

Answer: 39

Step-by-step explanation:

Given

P(x)=7x+5

r(x)=x-1

r(p(x))=7x+5-1=7x+4

so, r(p(5))

$\Rightarrow r(p(5))=7\times 5+4=35+4=39$

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Robert has 17 lb of grain he would like to put into sacks. Each sack will hold three pounds. How many sacks will he need?

satela [25.4K]

Answer:

Step-by-step explanation:

17/3=5.67

since you can't have 0.67 sack. you just round it up to 6

5 0

3 years ago

Read 2 more answers

Can someone help me find the equivalent expressions to the picture below? I’m having trouble

miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is $\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$ .

Now we will solve this expression with the help of law of exponents.

$\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}$

$=2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}$

$=2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}$

$=2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}$

$=2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }$ [Option 2]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$ [Option 1]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$

$=(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }$

$=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }$ [Option 3]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }$

$=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}$ [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0

3 years ago

Please help me i have a couple mins

finlep [7]

Answer:

x + 3

Step-by-step explanation:

Because he bought an unknown number of soccer balls that is where we use the variable, x. And we know that he bought 3 baseballs, and we add them both to get the total number of things bought. Hope this helped and you could give brainliest :)

7 0

3 years ago

Question

mixer [17]

The intervals are given as follows:

In range notation: [-282, 20,320].

In set-builder notation: {x|x ∈ ℝ, -282 <= x <= 20,320}

<h3>What is the range of elements notation for interval?</h3>

The range of elements notation for interval is given by:

[a,b].

In which:

a is the smallest value.

b is the greatest value.

In this problem these values are given by:

a = -282, b = 20,320.

Hence the interval in range notation is given by:

[-282, 20,320].

<h3>How to write the interval in set-builder notation?</h3>

The same interval can be written as follows, using set-builder notation?

{x|x ∈ ℝ, a <= x <= b}

Hence, for the situation described in this problem, the set-builder notation for the values is:

{x|x ∈ ℝ, -282 <= x <= 20,320}

More can be learned about notation of intervals at brainly.com/question/27896097

#SPJ1

5 0

2 years ago

Find the error and explain why:

Sloan [31]

1) 9x + 2 = x + 5 ---> 9x + 2 = 6

subtracted X from one side but not the other

2) 3(x-4) + 5 = 12 ---> 3x + 4 + 5 = 12

didn't distribute correctly: 3(x-4)

multiplied the X by 3 but not the -4

5 0

3 years ago