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Arturiano [62]
3 years ago
5

Please help me i have a couple mins

Mathematics
1 answer:
finlep [7]3 years ago
7 0

Answer:

x + 3

Step-by-step explanation:

Because he bought an unknown number of soccer balls that is where we use the variable, x. And we know that he bought 3 baseballs, and we add them both to get the total number of things bought. Hope this helped and you could give brainliest :)

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Please answer this correctly
TiliK225 [7]

Answer:

22 meters

Step-by-step explanation:

Area of yellow rectangle: 6x4=24

Area of gray rectangle: 8x=24

x=3

Thus, the perimeter is 3+3+8+8, which is 22.

5 0
3 years ago
Read 2 more answers
Which answer choise discreabe the ratio 6:4 selcet all that apply
stiv31 [10]

Answer:

3x:4x for some real number x

Step-by-step explanation:

Since answer choices weren't provided, I generalized my answer.

First, notice we can simplify 6:4 into 3:2 because we can write the ratio as a fraction and simplify (6 and 4 are both multiples of 2).

Since 3 and 2 are relatively prime and the ratio cannot simplify anymore, we can say that the ratio of 6:4 = 3:2 = 3x:2x for some real number x because we can see that 3x:2x = 3:2  by simplifying  (3x and 3 are both multiples of x).

As long as the answer choice you choose matches the format above, you should be correct! I hope this helps! :)

8 0
3 years ago
Three of the sides will require fencing and the fourth wall already exists.
kobusy [5.1K]

Answer:kind of hard try 3x-x+2=4

Step-by-step explanation:

8 0
3 years ago
An algorithm takes 0.5 seconds to run on an input of size 100. How long will it take to run on an input of size 1000 if the algo
dexar [7]

Answer:

linear: 5s

quadratic: 50s

log-linear: 0.75 s

cubic: 500s

Step-by-step explanation:

Let t_1,t_2 be the running time associated with the input of sizes s_1,s_2

If the running time is linear

t_2 = t_1\frac{s_2}{s_1} = 0.5*\frac{1000}{100} = 0.5*10 = 5s

If the running time is quadratic

t_2 = t_1\left(\frac{s_2}{s_1}\right)^2 = 0.5*\left(\frac{1000}{100}\right)^2 = 0.5*10^2 = 50s

If the running time is log-linear

t_2 = t_1\frac{log(s_2)}{log(s_1)} = 0.5*\frac{log(1000)}{log(100)} = 0.5*1.5 = 0.75s

If the running time is cubic:

t_2 = t_1\left(\frac{s_2}{s_1}\right)^3 = 0.5*\left(\frac{1000}{100}\right)^3 = 0.5*10^3 = 500s

6 0
3 years ago
Minimum point of the quadratic x^2+6x-2
WITCHER [35]

Answer:

(-3,-11)

Step-by-step explanation:

Compare the given quadratic equation with the general quadratic equation.

a=1, b=6 and c=-2

x=-\dfrac{(6)}{2(1)}\\=-3

Subsitute -3 for x in given quadratic equation.

y=(-3)^2+6(-3)-2\\=9-18-2\\=-11

The minimum point is (-3,-11).

3 0
3 years ago
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