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Olegator [25]
3 years ago
15

What is the value of x? What is the value of y?

Mathematics
1 answer:
Rudik [331]3 years ago
6 0

Answer:

Y= 20

X= 25

Step-by-step explanation:

The angles of a triangle have to equal 180

So

80+60 = 140

180 - 140 = 40

40/2 = 20

Y = 20

The angles of a linear line split equal 180

So

2y is one side of it which we learned Y = 20 which makes that side 40

To find the other side just guess and check

6(25) = 150

150 - 10 = 140

So the 2y = 40 and the (6x-10) = 140

So yea boom done

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Answer: d) 983 11/15 cm3

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3 years ago
Help me. The graph of a polynomial with unknown a is given. Write a polynomial
Xelga [282]

Answer:

f(x)=\dfrac{7}{20}\left(x+2\right)^{2}\left(x-1\right).

Step-by-step explanation:

If a graph touches the x-axis at x=c, then (x-c) is a factor of function.

From the given graph it is clear that the graph of function intersect x-axis at x=1 and touch the x-axis at x=-2.

It means (x-1) and (x+2) are not factors of given function but power of (x+2) must be 2.

So, the required function is

f(x)=a(x+2)^2(x-1)    ...(1)

where, a is a constant.

From the given figure it is clear that the graph passes through the point (-4,-7). So, substitute x=-4 and f(x)=-7 in the above function.

-7=a(-4+2)^2(-4-1)

-7=a(-2)^2(-5)

-7=-20a

\dfrac{7}{20}=a

Substitute a=\dfrac{7}{20} in (1).

f(x)=\dfrac{7}{20}(x+2)^2(x-1)

Therefore, the required function is f(x)=\dfrac{7}{20}(x+2)^2(x-1).

6 0
3 years ago
The slope of the line below is -2. Use the coordinates of the labeled point to
Vilka [71]

Answer:

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Step-by-step explanation:

Incomplete question:

There is no point to complete the equation.

As we have no point to complete the linear equation, we will solve for any given point (x0,y0) and a slope of m=-2.

The linear equation can be written generically as:

y(x)=mx+b\\\\y(x)=-2x+b

If a point, like (x0,y0) belongs to the linear equation, it satisfies its equation. Then:

y_0=-2x_0+b

Then, we can calculate b as:

y_0=-2x_0+b\\\\b=y_0+2x_0

We can express the equation for any linear equation with slope -2 and point (x0,y0) as:

y=-2x+(y_0+2x_0)\\\\y-y_0=-2(x-x_0)

6 0
3 years ago
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bixtya [17]
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3 years ago
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4 0
3 years ago
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