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Jlenok [28]
2 years ago
7

A 2-column table with 6 rows. The first column is labeled x with entries negative 4, negative 3, negative 2, negative 1, 0, 1. T

he second column is labeled f of x with entries negative 10, 0, 0, negative 4, negative 6, 0.
Which is a y-intercept of the continuous function in the table?
Mathematics
1 answer:
arlik [135]2 years ago
3 0

Hello,

\begin{array}{c|c|c|}&x&f(x)\\1&-4&-10\\2&-3&0\\3&-2&0\\4&-1&-4\\5&0&-6******\\6&1&0\\\end{array}\\

y-intercept is -6

If x=0 then y=-6

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Is (1, 4) a solution to the equation y = 7x?
olga nikolaevna [1]

Answer:

not a solution

Step-by-step explanation:

Substitute the point into the equation and see if it is true

y = 7x

4 = 7*1

4 = 7

This is not true so it is not a solution

8 0
3 years ago
A line with a slope of 5 passes through the point (2,10). What is its equation in slope intercept form
My name is Ann [436]

Answer:

The answer is

<h2>y = 5x</h2>

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

From the question

Slope / m = 5

Equation of the line passing through point (2 , 10) is

y - 10 = 5(x - 2)

y - 10 = 5x - 10

y = 5x - 10 + 10

<h3>y = 5x</h3>

Hope this helps you

5 0
3 years ago
Find m∠(CDE) please and thank you
skelet666 [1.2K]

Check the picture below.

4 0
3 years ago
Please Help !!!
solong [7]
Best Answer: 2 LiCl = 2 Li + Cl2
mass Li = 56.8 mL x 0.534 g/mL=30.3 g
moles Li = 30.3 g / 6.941 g/mol=4.37
the ratio between Li and LiCl is 2 : 2 ( or 1 : 1)

moles LiCl required = 4.37
mass LiCl = 4.37 mol x 42.394 g/mol=185.3 g


Cu + 2 AgNO3 = Cu/NO3)2 + 2 Ag
the ratio between Cu and AgNO3 is 1 : 2
moles AgNO3 required = 4.2 x 2 = 8.4 : but we have only 6.3 moles of AgNO3 so AgNO3 is the limiting reactant
moles Cu reacted = 6.3 / 2 = 3.15
moles Cu in excess = 4.2 - 3.15 =1.05

N2 + 3 H2 = 2 NH3
moles N2 = 42.5 g / 28.0134 g/mol=1.52
the ratio between N2 and H2 is 1 : 3
moles H2 required = 1.52 x 3 =4.56
actual moles H2 = 10.1 g / 2.016 g/mol= 5.00 so H2 is in excess and N2 is the limiting reactant
moles NH3 = 1.52 x 2 = 3.04
mass NH3 = 3.04 x 17.0337 g/mol=51.8 g
moles H2 in excess = 5.00 - 4.56 =0.44
mass H2 in excess = 0.44 mol x 2.016 g/mol=0.887 g
5 0
4 years ago
− 50 67 ​ +1.5−100%
Alex73 [517]

Answer:

<em>Hello, I think the answer is -0.84 Hope That Helps!</em>

8 0
3 years ago
Read 2 more answers
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