Answer: d. 512
Step-by-step explanation:
You need to remember that:
![(\sqrt[3]{x})^3=x](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7Bx%7D%29%5E3%3Dx)
Then, given the equation:
![\sqrt[3]{n}=8](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bn%7D%3D8)
You can find the value of "n" that make the equation true, by solving for "n".
So, to solve for "n", you need to raise both side of the equation to power 3. Therefore, you get:
![\sqrt[3]{n}=8](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bn%7D%3D8)
![(\sqrt[3]{n})^3=(8)^3](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7Bn%7D%29%5E3%3D%288%29%5E3)

Then, the value of "n" that makes the equation
true is: 512 (You can observe that this matches with the option d).
Answer:
A
Step-by-step explanation:
The student must have thought that every single arrowhead is a line of symmetry, so since there are 10 arrowheads, there must be 10 lines of symmetry. This is incorrect because if you look closely at the diagram, each line has 2 arrowheads, so the student is overcounting by a factor of 2. They should have just counted the number of lines, not arrowheads. Therefore, there must be 10/2 = 5 lines of symmetry, not 10. Hope this helps!
Answer:
56
Step-by-step explanation: