I believe that choice A is the best answer out of those given above.
Hope this helps and please enjoy Brainly! -ZeusROX
Answer:
Observe that the first and the second player have equal probability to get any of number. Using the principle of that symmetry, we have that

<u>Event X = 1 </u>means that the first player has got greater number than the second player, but not than the third player. So, choose any three numbers out of five of them and say that the minimal number out of these three goes to the second player, mean number to the first one and the largest to the third one. Permute remaining two numbers on remaining two people. Hence

<u>Event X = 2</u> means that the first player has got greater number than the second and the third player, but not than the fourth player. So, choose any four numbers out of five of them and say that the minimal number and the next minimal out of these four go to the second and the third player (and permute them), third number to the first one and the largest to the fourth player. Give remaining number to the last person. Hence

<u>Event X = 3</u> means that the first player has got greater number than the second, the third, and the forth player, but not than the fifth player. So, permute these five numbers as follows: give the highest to the last person, the second highest to the first, and permute remaining numbers on the remaining people. Hence

<u>Event X = 4</u> means basically the first player has won all the battles i.e, he has got the greatest number. Hence

Answer:
Step-by-step explanation:
The base of the cylinder is in the shape of a circle:
Area of the base=
For Base area=22 square units


Volume of the cylinder=
For volume '198 cubic units' the height(h) is:



Let the curve C be the intersection of the cylinder
and the plane
The projection of C on to the x-y plane is the ellipse
To see clearly that this is an ellipse, le us divide through by 16, to get
or
,
We can write the following parametric equations,
for
Since C lies on the plane,
it must satisfy its equation.
Let us make z the subject first,
This implies that,
We can now write the vector equation of C, to obtain,
The length of the curve of the intersection of the cylinder and the plane is now given by,
But
Therefore the length of the curve of the intersection intersection of the cylinder and the plane is 24.0878 units correct to four decimal places.
Answer:
One pendant costed $3.40
Step-by-step explanation: