Answer:
The data set with the greater range is the Girls
The greater median is the Girls at 110
Step-by-step explanation:
The range is the difference between the largest and smallest values.
As the largest value for the boys is 120 and the smallest is 60, the range would be 60
As the largest value for the girls is 150 and the smallest is 70, the range would be 80.
This means that the Girls have the greater range
The median is the number in the middle when the data is in ascending order.
As we have an even number, we will have to find the middle value between 5 and 6. To do this, we can add them together and divide them by 2.
The 5th boy in ascending order is 90 and the 6th boy is 90.
The 5th 5irl is 100 and the 6th girl is 120
This means that the median is greater for the Girls.
(-8)/(2y-8)=(5/(y+4))-7y+(8/(y^2-16))
(-4)/(y-4)=(5/(y+4))-7y+(8/(y+4)(y-4))
((-4)(y+4))/((y+4)(y-4))=((5(y-4))/(y+4)(y-4))-(7y(y+4)(y-4))/(y+4)(y-4))+(8/(y+4)(y-4))
(-4(y+4))=(5(y-4))-(7y(y+4)(y-4))+8
-4y-16=5y-20-(7y(y^2-16))+8
-4y-16=5y-20-7y^3+112y+8
-4y-16=117y-7y^3-12
-4=(121-7y^2)(y)
None of these choices would be equal to -4
Answer:
y= −1 + x/3
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
<span>5,286÷3
how many digits will the classroom number have
Notice that we have 4 digits as dividend with a place value of thousands as the
highest and to be divided with our divisor that have only 1 digit with a place value
of ones.
Now, let’s see how many digit will our quotient have:
=> 5 286 / 3
=> 1 762 is the quotient, it has still 4 digit with a place value of
thousands.
To check simply multiply our quotient and divisor.</span>
