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AleksandrR [38]
2 years ago
11

Nadia charges $7.50 an hour for babysitting. She babysits 18.5 hours the first week of the month and 20 hours the second week of

the month. To find her total earnings for those two weeks, Nadia writes 7.5 x 18.5 = 20 = $158.75. Explain her error. Show the correct solution.
Mathematics
1 answer:
melisa1 [442]2 years ago
5 0
7.5× 18.5=138.75 first week
7.5×20=$150 second week
total earnings 138.75+150=$288.75
She did multiply correctly 7.5 ×18.5 but got the wrong figure resulting in in lower pay and she did not multiply the 7.5 × 20 in the seond week. She shouldve added the week one and two wages to get her pay for 2 weeks
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A certain bacteria population is known to triples every 30 minutes. Suppose that there are initially 140 bacteria.
aivan3 [116]
I really wish i could help, I need an answer myswlf
8 0
3 years ago
What is the approximate value for the modal daily sales?
Aleksandr [31]

Answer:

Step-by-step explanation:

Hello!

<em>The table shows the daily sales (in $1000) of shopping mall for some randomly selected  days </em>

<em>Sales 1.1-1.5 1.6-2.0 2.1-2.5 2.6-3.0 3.1-3.5 3.6-4.0 4.1-4.5 </em>

<em>Days 18 27 31 40 56 55 23 </em>

<em>Use it to answer questions 13 and 14. </em>

<em>13. What is the approximate value for the modal daily sales? </em>

To determine the Mode of a data set arranged in a frequency table you have to identify the modal interval first, this is, the class interval in which the Mode is included. Remember, the Mode is the value with most observed frequency, so logically, the modal interval will be the one that has more absolute frequency. (in this example it will be the sales values that were observed for most days)

The modal interval is [3.1-3.5]

Now using the following formula you can calculate the Mode:

Md= Li + c[\frac{(f_{max}-f_{prev})}{(f_{max}-f_{prev})(f_{max}-f_{post})} ]

Li= Lower limit of the modal interval.

c= amplitude of modal interval.

fmax: absolute frequency of modal interval.

fprev: absolute frequency of the previous interval to the modal interval.

fpost: absolute frequency of the posterior interval to the modal interval.

Md= 3,100 + 400[\frac{(56-40)}{(56-40)+(56-55)} ]= 3,476.47

<em>A. $3,129.41 B. $2,629.41 C. $3,079.41 D. $3,123.53 </em>

Of all options the closest one to the estimated mode is A.

<em>14. The approximate median daily sales is … </em>

To calculate the median you have to identify its position first:

For even samples: PosMe= n/2= 250/2= 125

Now, by looking at the cumulative absolute frequencies of the intervals you identify which one contains the observation 125.

F(1)= 18

F(2)= 18+27= 45

F(3)= 45 + 31= 76

F(4)= 76 + 40= 116

F(5)= 116 + 56= 172 ⇒ The 125th observation is in the fifth interval [3.1-3.5]

Me= Li + c[\frac{PosMe-F_{i-1}}{f_i} ]

Li: Lower limit of the median interval.

c: Amplitude of the interval

PosMe: position of the median

F(i-1)= accumulated absolute frequency until the previous interval

fi= simple absolute frequency of the median interval.

Me= 3,100+400[\frac{125-116}{56} ]= 3164.29

<em>A. $3,130.36 B. $2,680.36 C. $3,180.36 D. $2,664</em>

Of all options the closest one to the estimated mode is C.

5 0
2 years ago
The first three terms of a geometric sequence are
Lisa [10]

Answer:

a4 = 128

a5 = -512

Step-by-step explanation:

a1= -2

q= (-1)^(n+1) × 4

a4 = a1q³ = (-2) (-4)³ = -2 × -64 = +128

a5 = a1q⁴ = (-2) (-4)⁴ = -2 × 256 = -512

3 0
2 years ago
What is the answer? I find this very confusing for me.
vichka [17]

Answer:

19

Step-by-step explanation:

If you want to find the answer of the equation, sub the given information into it:

z + xz + y

we know that:

x = 5

y = 1

z = 3

We got:

= 3 + 5*3 + 1

= 3 + 15 + 1

= 19

Hope this helped :3

5 0
3 years ago
Lin earned $50 last week. Andre earned 80% of what Lin earned. How much did Andre earn last week? *
DaniilM [7]

Answer:

$40

Step-by-step explanation:

Turn the percentage into a decimal.

80% = 0.8

Multiply.

50 * 0.8 = 40

Best of Luck!

5 0
2 years ago
Read 2 more answers
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