Answer:

Step-by-step explanation:

Data:
L₀ = 24 g
L = 20 g
k = 0.000 11 yr⁻¹
Calculation:

Answer:
Here, b represents one loaf of bread and m represents the one gallon of milk.
As per the statement:
Arah went to the grocery store and bought 4 loaves of bread and 1 gallon of milk for $12.
⇒
It is also given that the next week, Sarah bought 2 loaves of bread and 3 gallons of milk for $13.50.
⇒
Then; system of equation :
.....[1]
.....[2]
Solve for b and m using above system of equations.
Multiply equation [2] by 2 we get;
.....[3]
Subtract equation [1] from [3] we get;
Combine like terms;
Divide both sides by 5 we get;
m = $3
Substitute the value of m in equation [1] we get;

Subtract 3 from both sides we get;
Divide both sides by 4 we get;
b = $2.25
Therefore, cost of one loaf of bread (b) and one gallon of milk (m) are:
$2.25 ad $3
69% is the same as .69, which is the same as 69/100
I would but I’m stuck on this problem too
-4 isn't a real number because there is no square root of -4. However, there is a cube root of -8, because -2 * -2 * -2 = -8.