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umka21 [38]
3 years ago
13

Help am i correct please Ehejahrs

Mathematics
1 answer:
Sladkaya [172]3 years ago
4 0
I think sooooooo if not I’m very sorry
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PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! I DONT KNOW HOW TO GRAPH SO
xz_007 [3.2K]

Answer:

(-1, -2) will be the solution.

Step-by-step explanation:

System of equations has been given as,

y = 3x + 1 ---------(1)

Input-output value table for the given line will be,

x       -2        -1          0          1

y      -5        -2         1           4

y = -x - 3 ----------(2)

Input-output value table for the given line will be,

x        -2         -1           0           1

y       -1          -2          -3         -4  

By plotting the given coordinates we can draw the straight lines.

And the point of intersection (common point) of these lines will be the solution of the given system of equations.

Hence, (-1, -2) will be the solution.

4 0
2 years ago
A marathon is 46,145 yards (about 26 miles) long. If Terrence has run 23,561 yards, estimate by rounding to thousands the number
barxatty [35]

Given:

The length of the marathon is L= 46,145 yards.

The length covered by terrence is d = 23,561 yrads.

The objective is to find the remaining distance need to cover by terrence.

To calculate the remaining distance, we will use the relation,

x=L-d

On plugging the values in the above relation, we get,

\begin{gathered} x=46145-23561 \\ =22584\text{ yards} \\ \approx23000\text{ yards} \end{gathered}

Hence, Terrence needs to run about 23000 yards.

5 0
1 year ago
Use a surface integral to find the general formula for the surface area of a cone with height latex: h and base radius latex: a(
BlackZzzverrR [31]
We can parameterize this part of a cone by

\mathbf s(u,v)=\left\langle u\cos v,u\sin v,\dfrac hau\right\rangle

with 0\le u\le a and 0\le v\le2\pi. Then

\mathrm dS=\|\mathbf s_u\times\mathbf s_v\|\,\mathrm du\,\mathrm dv=\sqrt{1+\dfrac{h^2}{a^2}}u\,\mathrm du\,\mathrm dv

The area of this surface (call it \mathcal S) is then

\displaystyle\iint_{\mathcal S}\mathrm dS=\sqrt{1+\frac{h^2}{a^2}}\int_{v=0}^{v=2\pi}\int_{u=0}^{u=a}u\,\mathrm du\,\mathrm dv=a^2\sqrt{1+\frac{h^2}{a^2}}\pi=a\sqrt{a^2+h^2}\pi
6 0
3 years ago
Which property could be used to find the missing number?
liraira [26]
The correct awnser is B..
7 0
3 years ago
Which set of values could be the side lengths of a 30-60-90 triangle?
yulyashka [42]
C). 6*6√2*12 is your answer.... i think 
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3 years ago
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