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2 years ago

What relationships exist between the figures on the coordinate grid below?

Mathematics

1 answer:

lbvjy [14]2 years ago

5 0

Answer: the relations would be where the line meets the corner of a square where both x and y have a number

Step-by-step explanation:

if you showed a picture of the graph it would help, but where the line of solutions meets a corner

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What is 3 and 1/5 as a decimal

Musya8 [376]

Answer:

3.2

Step-by-step explanation:

1/5=0.2

3 + 0.2 = 3.2

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2 years ago

Help ineed to find this.

omeli [17]

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3 years ago

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I need to know how to subtract fractions 4 2/3 - 3/4

sergij07 [2.7K]

Answer: The answer would be 3.91666666667

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2 years ago

Some students are working together to draw a picture of a playground.

vodomira [7]

From the information provided by the statement, you know that

*Ann draws 2/16 of the playground

*Susan draws 6/16 of the playground because she draws 3 times as much as Ann so

$3\cdot\frac{2}{16}=\frac{3}{1}\cdot\frac{2}{16}=\frac{6}{16}$

*Louise draws 3/16 because she draws half as much as Susan, so

$\frac{1}{2}\cdot\frac{6}{16}=\frac{6}{32}=\frac{2\cdot3}{2\cdot16}=\frac{3}{16}$

*Sam draws 2/16 because she draws 1 less section than Louise

$\frac{3}{16}-\frac{1}{16}=\frac{2}{16}$

Now, let x be the fraction of the playground that still needs to be drawn. Then, you have

$\begin{gathered} \frac{2}{16}+\frac{6}{16}+\frac{3}{16}+\frac{2}{16}+x=\frac{16}{16} \\ \text{ Add similar terms} \\ \frac{13}{16}+x=\frac{16}{16} \\ \text{ Subtract }\frac{13}{16}\text{from both sides of the equation} \\ \frac{13}{16}-\frac{13}{16}+x=\frac{16}{16}-\frac{13}{16} \\ x=\frac{3}{16} \end{gathered}$

Therefore, 3/16 of the playground still needs to be drawn.

5 0

10 months ago

A) b=2 i used cos

ivann1987 [24]

Answer:

sin 30=B/C

1/2=B/C

2B=C

B=C/2

3 0

2 years ago