Can someone please help me I really need it
2 answers:
You might be interested in
Answer:
96% confidence interval estimate for the mean monthly rent of all unmarried BYU students in winter 2018 is [335.89 , 356.10].
Step-by-step explanation:
We are given that a group of researchers at the BYU Off-Campus Housing department want to estimate the mean monthly rent that unmarried BYU students paid during winter 2018.
During March 2018, they randomly sampled 314 BYU students and found that on average, students paid $346 for rent with a standard deviation of $86.
So, the pivotal quantity for 95% confidence interval for the average age is given by;
P.Q. = ~
where, = average rent paid by 314 BYU students = $346
s = sample standard deviation = $86
n = sample of students = 314
= population mean monthly rent of all unmarried BYU students
So, 96% confidence interval for the population mean monthly rent, is ;
P(-2.082 < < 2.082) = 0.96
P(-2.082 < < 2.082) = 0.96
P( <
<
) = 0.96
P( <
<
) = 0.96
96% confidence interval for = [
,
]
= [ ,
]
= [335.89 , 356.10]
Therefore, 96% confidence interval estimate for the mean monthly rent of all unmarried BYU students in winter 2018 is [335.89 , 356.10].
Answer:
≈ 35.1 ft
Step-by-step explanation:
The model is a right triangle with ladder being the hypotenuse and the angle between the ground and the ladder is 70°
Using the cosine ratio, with l being the length of the ladder.
cos70° = =
( multiply both sides by l )
l × cos70° = 12 ( divide both sides by cos70° )
l = ≈ 35.1 ( to the nearest tenth )
The ladder is approx 35.1 ft long