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3 years ago

Can someone please help me I really need it

Mathematics

2 answers:

Andreas93 [3]3 years ago

8 0

Check the picture below

notice, both triangles are 45-45-90 triangles, so if one has a base of 26, so does the other

Lesechka [4]3 years ago

4 0

Download the app Slater! You put in the title of any text book and it'll pop up.

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Is (x + 6) a factor of f(x) = x3 − 3x2 + 2x − 8? Show how to use either the remainder theorem or the factor theorem to explain y

inysia [295]

Answer:

x + 6 is not a factor of f ( x ) = x³ - 3x² + 2x - 8 because when -6 is substituted into the function, the answer is not 0.

Step-by-step explanation:

→ Substitute x = -6 into f ( x )

( 6 )³ - 3 × ( 6 )² + ( 2 × 6) - 8

→ Simplify

216 - 108 + 12 - 8

→ Simplify further

112

7 0

2 years ago

I need help plssssssssssssssssssssssss

lesya692 [45]

Answer:

great

Step-by-step explanation:

6 0

4 years ago

Read 2 more answers

Which system of equations models the word problem on the left?

My name is Ann [436]

Answer: c

2H+3C= 4.95

3H+2C= 5.45

Step-by-step explanation:

4 0

3 years ago

How are the graphs of the functions f(x) = √16^x and g(x) =3√64^x related?

liberstina [14]

Answer:- The functions f(x) and g(x) are equivalent.

Explanation:-

Given functions:- $f(x)=\sqrt{16^x}$ and $g(x)=\sqrt[3]{64^x }$

Simplify the functions by using law of exponents

$(a^n)^m=a^{nm}$

Thus $f(x)=\sqrt{16^x}=\sqrt{(4^2)^x}=\sqrt{4^{2x}} =\sqrt{(4^x)^2}=4^x$

and $g(x)=\sqrt[3]{64^x}=\sqrt[3]{(4^3)^x}= \sqrt[3]{4^{3x}}= \sqrt[3]{(4^x)^3}=4^x$

⇒f(x)=g(x)

Therefore ,the functions f(x) and g(x) are equivalent.

7 0

3 years ago

Read 2 more answers

Hello, I'm trying to solve 6x + y = 4, x - 4y = 19. I have found the y but I cant seem to find the x. Plz help and we cant use d

gizmo_the_mogwai [7]

Answer:

$x=\frac{7}{5}$

$y=-\frac{22}{5}$

Step-by-step explanation:

Given:

The given expressions are.

$6x+y=4$

$x-4y=19$

We need to find x and y values.

Solution:

Equation 1⇒ $6x+y=4$

Equation 2⇒ $x-4y=19$

First solve the equation 1 for y.

$6x+y=4$

$y = 4-6x$ --------(3)

Substitute $y = 4-6x$ in equation 2.

$x-4(4-6x)=19$

Simplify.

$x-(4\times 4 - 4\times 6x)=19$

$x-(16-24x)=19$

$x-16+24x=19$

Add 16 both side of the equation.

$25x-16+16=19+16$

$25x=35$

$x=\frac{35}{25}$

Divide Numerator and denominator by 5.

$x=\frac{7}{5}$

Substitute x value in equation 3 and simplify.

$y=4-6(\frac{7}{5})$

$y=4-\frac{6\times 7}{5}$

$y=4-\frac{42}{5}$

$y=\frac{5\times 4-42}{5}$

$y=\frac{20-42}{5}$

$y=-\frac{22}{5}$ .

Therefore, the value of $x=\frac{7}{5}$ and $y=-\frac{22}{5}$ .

6 0

4 years ago

Can someone​ please help me I really need it

Can someone please help me I really need it