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Igoryamba
3 years ago
15

The radius of a circle is 25 centimeters.

Mathematics
1 answer:
iragen [17]3 years ago
6 0

Answer:

157.08

Step-by-step explanation:

The formula for circumference is 2πr.

2πr = 2π25 = 50π = 157.079 = 157.08

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The stopping distance, D, in feet of a car is directly proportional to the square of it's speed, V. Write the direct variation e
kow [346]

Answer:

D=kV^2

Step-by-step explanation:

In this problem, it is given that,

The stopping distance, D, in feet of a car is directly proportional to the square of it's speed, V.

We need to write the direct variation equation for the scenario above. It can be given by :

D\propto V^2

To remove the constant of proportionality, we put k.

D=kV^2

k is any constant

Hence, this is the required solution.

4 0
3 years ago
In the diagram, ΔPMN ≅ ΔQSR<br><br> If QR = 20 in., RS = 7 in., and SQ = 24 in., what is PN
Tamiku [17]
PN=20
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4 years ago
Read 2 more answers
Can someone please help me on number 16-ABC
melomori [17]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the inequality

-2x < 10

-6 < -2x

<u>Part a) Is x = 0 a solution to both inequalities</u>

FOR  -2x < 10

substituting x = 0 in -2x < 10

-2x < 10

-3(0) < 10

0 < 10

TRUE!

Thus, x = 0 satisfies the inequality -2x < 10.

∴ x = 0 is the solution to the inequality -2x < 10.

FOR  -6 < -2x

substituting x = 0 in -6 < -2x

-6 < -2x

-6 < -2(0)

-6 < 0

TRUE!

Thus, x = 0 satisfies the inequality -6 < -2x

∴ x = 0 is the solution to the inequality -6 < -2x

Conclusion:

x = 0 is a solution to both inequalites.

<u>Part b) Is x = 4 a solution to both inequalities</u>

FOR  -2x < 10

substituting x = 4 in -2x < 10

-2x < 10

-3(4) < 10

-12 < 10

TRUE!

Thus, x = 4 satisfies the inequality -2x < 10.

∴ x = 4 is the solution to the inequality -2x < 10.

FOR  -6 < -2x

substituting x = 4 in -6 < -2x

-6 < -2x

-6 < -2(4)

-6 < -8

FALSE!

Thus, x = 4 does not satisfiy the inequality -6 < -2x

∴ x = 4 is the NOT a solution to the inequality -6 < -2x.

Conclusion:

x = 4 is NOT a solution to both inequalites.

Part c) Find another value of x that is a solution to both inequalities.

<u>solving -2x < 10</u>

-2x\:

Multiply both sides by -1 (reverses the inequality)

\left(-2x\right)\left(-1\right)>10\left(-1\right)

Simplify

2x>-10

Divide both sides by 2

\frac{2x}{2}>\frac{-10}{2}

x>-5

-2x-5\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-5,\:\infty \:\right)\end{bmatrix}

<u>solving -6 < -2x</u>

-6 < -2x

switch sides

-2x>-6

Multiply both sides by -1 (reverses the inequality)

\left(-2x\right)\left(-1\right)

Simplify

2x

Divide both sides by 2

\frac{2x}{2}

x

-6

Thus, the two intervals:

\left(-\infty \:,\:3\right)

\left(-5,\:\infty \:\right)

The intersection of these two intervals would be the solution to both inequalities.

\left(-\infty \:,\:3\right)  and \left(-5,\:\infty \:\right)

As x = 1 is included in both intervals.

so x = 1 would be another solution common to both inequalities.

<h3>SUBSTITUTING x = 1</h3>

FOR  -2x < 10

substituting x = 1 in -2x < 10

-2x < 10

-3(1) < 10

-3 < 10

TRUE!

Thus, x = 1 satisfies the inequality -2x < 10.

∴ x = 1 is the solution to the inequality -2x < 10.

FOR  -6 < -2x

substituting x = 1 in -6 < -2x

-6 < -2x

-6 < -2(1)

-6 < -2

TRUE!

Thus, x = 1 satisfies the inequality -6 < -2x

∴ x = 1 is the solution to the inequality -6 < -2x.

Conclusion:

x = 1 is a solution common to both inequalites.

7 0
3 years ago
Which function is the inverse of f(x) = –5x – 4?
Finger [1]

Answer:

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Step-by-step explanation:

Given is a function

f(x) = -5x-4\\

To find its inverse.

We must check whether f is one to one or onto first

If -5x1-4 = -5x2-4 we get x1=x2

Hence f is one to one

Also for every f(x) we can find a x so f is onto.

So inverse exists

Let

y=-5x-4\\-5x=y+4\\x=\frac{-1}{5} (y+4)

Replace x by f inverse and y by x

f^(-1)(x) = \frac{-1}{5} (x+4)

7 0
4 years ago
A bag has 2 red marbles, 1 blue marble and 4 gold marbles. What is the probability of
Aliun [14]

Answer:

c

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Step-by-step explanation:

8 0
4 years ago
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