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padilas [110]
3 years ago
11

I need help with finding the area of the following triangles

Mathematics
1 answer:
svetlana [45]3 years ago
5 0
1) 1/2 x (4)(3) = 1/2 x 12=6in2
2) 1/2 x (12)(6) = 1/2 x 36=18cm2
3) 1/2 x (9)(7) = 1/2 x 63=31.5ft2
4) 1/2 x (12)(12) = 1/2 x 144= 72cm2
5) 1/2 x (3)(2) = 1/2 x 6=3ft2
6) 1/2 x (20)(16) = 1/2 x 320=160cm2
7) 1/2 x (7)(15) = 1/2 x 105=52.5m2
8) 1/2 x (9)(9) = 1/2 x 81=40.5in2
9) 1/2 x (2)(2) = 1/2 x 4=2ft2
10) 1/2 x (6)(4) = 1/2 x 24=12ft2
11) 1/2 x (15)(10) = 1/2 x 150=75ft2
12) 1/2 x (3)(10) = 1/2 x 30=15m2
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Find the missing factor
Yuki888 [10]

Answer:

The missing factor is (9s+1)

Step-by-step explanation:

The missing factor is (9s+1) because of the following

(9s^2 + s) + (18s+2)

If we factor out s from 9s^2+s, we get s(9s+1).

If we factor out 2 from 18s+2, we get 2(9s+1)

putting these together, we get s(9s+1) + 2(9s+1). Factoring out the common term of 9s+1, we get (9s+1)(s+2). therefore, the missing factor is 9s+1

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What is the least common denominator of the rational expressions below?
Lyrx [107]

Answer:

B.(x-6)

Step-by-step explanation:

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2 years ago
When dividing the polynomial 3x3 - 5x2 - 4x + 4 by (x - 2), the remainder is 0, making (x - 2) a factor.
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3 years ago
In the diagram, the circle will be dilated by a scale factor of 3 about the origin. The points C, A, and B map to C', A', and B'
stellarik [79]
Original coordinates of the points:
A (8,15) ; B (12,13) ; C (8,10)

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A ⇒ 3x = 3(8) = 24 ; 3y = 3(15) = 45 ⇒ A' (24,45)
B ⇒ 3x = 3(12) = 36 ; 3y = 3(13) = 39 ⇒ B' (36, 39)
C ⇒ 3x = 3(8) = 24 ; 3y = 3(10) = 30 ⇒ C' (24, 30)

The given image forms a right triangle. So, I'll get the short leg and long leg of the right triangle to solve for the hypotenuse, length of CB.

Short leg: y value of B and C
39 - 30 = 9

Long leg: x value of B and C
36 - 24 = 12

a² + b² = c²
9² + 12² = c²
81 + 144 = c²
225 = c²
√225 = √c²
15 = c

The length of CB is 15 units.
4 0
3 years ago
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