Answer: 8π square meters
Explanation:
First, we convert the angle of the sector to radians, which is 30 degrees.
Note that 180 degrees is equal to π radians. Since 30 degrees is equal to 180 degrees divided by 6,
30 degrees = π/6 radians
Thus, the angle of the sector in radians is π/6.
So, the area of the sector is given by
(Area of sector) = (1/2)(radius)²(angle of the sector in radians)
= (1/2)(radius)²(π/6)
= (π/12)(radius)²
= (1/12)(π)(radius)²
Note that
(Area of the circle) = (π)(radius)² = 96π
Therefore, the area of the 30-degree sector is given by
(Area of the sector) = (1/12)(π)(radius)²
= (1/12)(Area of the circle)
= (1/12)(96π)
(Area of the sector) = 8π square meters
Hello there! I can help you! So there is one blue counter added to two green counters. To solve this problem, we can write and solve an equation. Set it up like this:
12 + 1x = 8 + 2x
We do this, because there are already some of each color in the bag. 1x makes one counter each and 2x is two counters for every blue counter in the bag. Let's solve it. Subtract 1x from each side. 1x - 1x cancels out. 2x - 1x is 1x or just simply x. That simplifies to 12 = 8 + x. Subtract 8 from each side to get the variable by itself. 8 - 8 cancels out. 12 - 8 is 4. That leaves 4 = x. Nothing else needs to be done. Let's plug the value in and see if it works. 1 * 4 is 4. 12 + 4 is 16. 2 * 4 is 8. 8 + 8 is 16. 16 = 16. There. x = 4. 4 blue counters and 8 green counters were added to the bag.
Given:
The vertices of a polygon QRST are T(-2, 3), Q(1, 5), R(3, -1) and S(0, 0).
To find:
The vertices for 
.
Solution:
The rule represents refection of polygon QRST across the x-axis.
If a figure is reflected across the x-axis, then
Using this rule, we get
Therefore, the vertices for are T'(-2, -3), Q'(1, -5), R'(3, 1) and S'(0, 0).
I got the answer 10 if not sorry
Can you show us all the graphs
