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alexdok [17]
3 years ago
15

Answers: a) 74 b) 108 c)49 d)51

Mathematics
2 answers:
lisabon 2012 [21]3 years ago
5 0

Answer:

51

Step-by-step explanation:

sum of exterior angles = 360

64  + 60 + 69 + 42 + x + x +23 = 360

2x + 258 = 360

2x = 360 - 258

2x = 102

x = 51

Mashcka [7]3 years ago
4 0

Answer:

The person below me is correct

Step-by-step explanation:

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Marysya12 [62]

Answer:

-3\sqrt{3}

Step-by-step explanation:

-4\sqrt{12}+\sqrt{75}

-4\sqrt{4*3}+\sqrt{25*3}

-4\sqrt{4}\sqrt{3}+\sqrt{25}\sqrt{3}

-4(2)\sqrt{3}+5\sqrt{3}

-8\sqrt{3}+5\sqrt{3}

-3\sqrt{3}

5 0
2 years ago
If 5/2 kg of carrots cost $3,how much will 3/2 kg cost?​
VashaNatasha [74]

Answer:

first you find out how much will 1/2 kg of carrot cost, that way you can multiply it by 3 to get what 3/2 cost.

So, 3÷ 5 = 0.6 per 1/2 kg. Then 0.6 × 3 = 1.8 dollars for 3/2 kg

7 0
3 years ago
With Obesity on the rise, a Doctor wants to see if there is a linear relationship between the Age and Weight and estimating a pe
Romashka [77]

Answer:

112.569 ( D )

Step-by-step explanation:

Applying the estimated Regression Equation

y = b1X1 + b2X2 + a

b1 = ((SPX1Y)*(SSX2)-(SPX1X2)*(SPX2Y)) / ((SSX1)*(SSX2)-(SPX1X2)*(SPX1X2)) = 596494.5/635355.88 = 0.93884

b2 = ((SPX2Y)*(SSX1)-(SPX1X2)*(SPX1Y)) / ((SSX1)*(SSX2)-(SPX1X2)*(SPX1X2)) = 196481.5/635355.88 = 0.30925

a = MY - b1MX1 - b2MX2 = 149.25 - (0.94*61.31) - (0.31*193.88) = 31.73252

y = 0.939X1 + 0.309X2 + 31.733

For x1 ( age ) =39, and  x2(weight) =143

y = (0.93884*39) + (0.30925*143) + 31.73252= 112.569

where

Sum of X1 = 981

Sum of X2 = 3102

Sum of Y = 2388

Mean X1 = 61.3125

Mean X2 = 193.875

Mean Y = 149.25

attached is the Tabular calculation of the required values needed for estimated regression equation

8 0
3 years ago
Need the answer fast question is on the problem will mark brainliest<br> NO LINKS PLEASE
Fed [463]
It’s the last one & the second one
6 0
2 years ago
X² + y² = 8
ohaa [14]

Answer:

(2,2)~ \text{and}~ (-2,-2)

Step by step explanation:

x^2 +y^2 =8~~~~~~...(i)\\\\x-y=0~~~~~~~~~...(ii)\\\\\text{From (ii):}\\\\x-y = 0 \implies x = y\\\\\text{Substitute x = y  in eq (i):}\\\\~~~~~~y^2 +y^2 =8\\\\\implies 2y^2 = 8\\ \\\implies y^2 = \dfrac 82\\\\\implies y^2 = 4\\\\\implies y = \pm\sqrt 4\\\\\implies y = \pm 2\\\\\text{Substitute y = x  in equation (i):}\\ \\~~~~~~x^2 +x^2 = 8\\ \\\implies 2x^2 = 8\\\\\implies x^2 = \dfrac 82\\\\\implies x^2 = 4\\\\\implies x = \pm\sqrt 4\\\\\implies x = \pm2\\\\

\text{Hence,}~ (x,y) = (\pm2, \pm 2)

3 0
2 years ago
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