WHO WANTS TO BE MY BSF? IF YOU DON'T....... THENNNN OH WELLLLLLLLLLLL
2 answers:
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Answer:
The probability is
Step-by-step explanation:
We can divide the amount of favourable cases by the total amount of cases.
The total amount of cases is the total amount of ways to put 8 rooks on a chessboard. Since a chessboard has 64 squares, this number is the combinatorial number of 64 with 8,
For a favourable case, you need one rook on each column, and for each column the correspondent rook should be in a diferent row than the rest of the rooks. A favourable case can be represented by a bijective function with A = {1,2,3,4,5,6,7,8}. f(i) = j represents that the rook located in the column i is located in the row j.
Thus, the total of favourable cases is equal to the total amount of bijective functions between a set of 8 elements. This amount is 8!, because we have 8 possibilities for the first column, 7 for the second one, 6 on the third one, and so on.
We can conclude that the probability for 8 rooks not being able to capture themselves is
Answer:
8.9 meters
Step-by-step explanation:
this seems like a problem where you can use the pythagorean theorem:
you know one of the two legs (6m) and the hypotenuse (9m), you must find the other leg
a^2 + 6^2 = 9^2
a^2 + 36 = 81
a^2 = 45
a = or
·
which simplifies to be 3
or approx. 8.9 meters