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3 years ago

F(x) = 2x and g(x) = x + 1, find f(3) and find gf(3)

Mathematics

1 answer:

lord [1]3 years ago

8 0

Answer:

6 and 7

Step-by-step explanation:

To evaluate f(3), substitute x = 3 into f(x) , that is

f(3) = 2(3) = 6

To evaluate g(f(3)), substitute f(3) = 6 into g(x)

g(6) = 6 + 1 = 7

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3 years ago

40% of Oatypop cereal boxes contain a prize. Hannah plans to keep buying cereal until she gets a prize. What is the probability

aleksley [76]

Answer:

$(0.6)^{n}+n(0.4)(0.6)^{n-1}+\frac{n(n-1)(0.4)^{2}0.6^{n-2}}{2} +\frac{n(n-1)(n-2)0.4^{3}0.6^{n-3}}{6}$

Step-by-step explanation:

We will use the binomial distribution. Let X be the random variable representing the no. of boxes Hannah buys before betting a prize.

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Then failure q = 1-0.4 = 0.6

Hannah keeps buying cereal boxes until she gets a prize. Then n be no. times she buys the boxes.

P(X ≤ 3) = P(X=0) +P(X=1)+P(X=2)+P(X=3)

= $\binom{n}{0}p^{0}q^{n-0}$ + $\binom{n}{1}p^{1}q^{n-1}$ + $\binom{n}{2}p^{2}q^{n-2}$ + $\binom{n}{3}p^{3}q^{n-3}$

= $q^{n}+npq^{n-1}$ + $\frac{n(n-1)(p)^{2}q^{n-2}}{2}$ + $\frac{n(n-1)(n-2)p^{3}q^{n-3}}{6}$

= $(0.6)^{n}+n(0.4)(0.6)^{n-1}+[tex]\frac{n(n-1)(0.4)^{2}0.6^{n-2}}{2} +\frac{n(n-1)(n-2)0.4^{3}0.6^{n-3}}{6}$

7 0

3 years ago

Read 2 more answers

I didn't get how you wrote 1.75 like how did it come there?

sertanlavr [38]

Answer:

Uhh what??

Step-by-step explanation:

Do you mean like 1.75 in a decimal form??

4 0

3 years ago

Need a quick answer please

Zanzabum

Answer:

8 fits the equation

Step-by-step explanation:

hope this helps

4 0

3 years ago