Answer:
with? TwT mental? physical?
Step-by-step explanation:
Answer:
hi there ☺️
Here we will use algebra to find three consecutive integers whose sum is 345. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 345. Therefore, you can write the equation as follows:
(X) + (X + 1) + (X + 2) = 345
To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:
X + X + 1 + X + 2 = 345
3X + 3 = 345
3X + 3 - 3 = 345 - 3
3X = 342
3X/3 = 342/3
X = 114
Which means that the first number is 114, the second number is 114 + 1 and the third number is 114 + 2. Therefore, three consecutive integers that add up to 345 are 114, 115, and 116.
114 + 115 + 116 = 345
We know our answer is correct because 114 + 115 + 116 equals 345 as displayed above.
Step-by-step explanation:
pls rate me the brainiest
4.29 + 97.2 + 0.687 = 102.177
In adding decimal numbers, make sure that the decimal points are aligned. Since each number has different counts of numbers after the decimal point, use 0 to pad the missing places.
4.290
97.200
<u> 0.687
</u> 102.177
The count of numbers after the decimal point is the same count of number of the decimal who has the greatest count of number after the decimal point.
4.29 only has 2 counts of places after the decimal point
97.2 only has 1 count of place after the decimal point
0.687 has 3 counts of places after the decimal point.
The sum of the decimals must also have 3 counts of places after the decimal point.
Answer: 8/2
Step-by-step explanation:
