Answer:
2km
Step-by-step explanation:
Distance = Speed ÷ Time
Distance = 3 ÷ 1.5 (as 1 hour and 30 minutes is an hour and a half)
Distance = 2km
The measures of center and variability for the
temperatures that were lower this week than last week include mean, range, mean absolute deviation.
<h3>What is a mean?</h3>
It should be noted that a mean simply means the average set if numbers given.
Also, the range is the difference between the highest number and the lowest number in the data.
Learn more about mean on:
brainly.com/question/1136789
#SPJ1
Answer:
62390
Step-by-step explanation:
you have to round up if it's 5 or more and round down if it's less.
Answer: 6
Steps:
7 + 11 + 0 = 18
18/3 = 6
Answer:
(a)123 km/hr
(b)39 degrees
Step-by-step explanation:
Plane X with an average speed of 50km/hr travels for 2 hours from P (Kano Airport) to point Q in the diagram.
Distance = Speed X Time
Therefore: PQ =50km/hr X 2 hr =100 km
It moves from Point Q at 9.00 am and arrives at the airstrip A by 11.30am.
Distance, QA=50km/hr X 2.5 hr =125 km
Using alternate angles in the diagram:
![\angle Q=110^\circ](https://tex.z-dn.net/?f=%5Cangle%20Q%3D110%5E%5Ccirc)
(a)First, we calculate the distance traveled, PA by plane Y.
Using Cosine rule
![q^2=p^2+a^2-2pa\cos Q\\q^2=100^2+125^2-2(100)(125)\cos 110^\circ\\q^2=34175.50\\q=184.87$ km](https://tex.z-dn.net/?f=q%5E2%3Dp%5E2%2Ba%5E2-2pa%5Ccos%20Q%5C%5Cq%5E2%3D100%5E2%2B125%5E2-2%28100%29%28125%29%5Ccos%20110%5E%5Ccirc%5C%5Cq%5E2%3D34175.50%5C%5Cq%3D184.87%24%20km)
SInce aeroplane Y leaves kano airport at 10.00am and arrives at 11.30am
Time taken =1.5 hour
Therefore:
Average Speed of Y
![=184.87 \div 1.5\\=123.25$ km/hr\\\approx 123$ km/hr (correct to three significant figures)](https://tex.z-dn.net/?f=%3D184.87%20%5Cdiv%201.5%5C%5C%3D123.25%24%20km%2Fhr%5C%5C%5Capprox%20123%24%20km%2Fhr%20%28correct%20to%20three%20significant%20figures%29)
(b)Flight Direction of Y
Using Law of Sines
![\dfrac{p}{\sin P} =\dfrac{q}{\sin Q}\\\dfrac{125}{\sin P} =\dfrac{184.87}{\sin 110}\\123 \times \sin P=125 \times \sin 110\\\sin P=(125 \times \sin 110) \div 184.87\\P=\arcsin [(125 \times \sin 110) \div 184.87]\\P=39^\circ $ (to the nearest degree)](https://tex.z-dn.net/?f=%5Cdfrac%7Bp%7D%7B%5Csin%20P%7D%20%3D%5Cdfrac%7Bq%7D%7B%5Csin%20Q%7D%5C%5C%5Cdfrac%7B125%7D%7B%5Csin%20P%7D%20%3D%5Cdfrac%7B184.87%7D%7B%5Csin%20110%7D%5C%5C123%20%5Ctimes%20%5Csin%20P%3D125%20%5Ctimes%20%5Csin%20110%5C%5C%5Csin%20P%3D%28125%20%5Ctimes%20%5Csin%20110%29%20%5Cdiv%20184.87%5C%5CP%3D%5Carcsin%20%5B%28125%20%5Ctimes%20%5Csin%20110%29%20%5Cdiv%20184.87%5D%5C%5CP%3D39%5E%5Ccirc%20%24%20%28to%20the%20nearest%20degree%29)
The direction of flight Y to the nearest degree is 39 degrees.