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3 years ago

How do you write 2x-3y=-15 In slope intercept form?

2 answers:

8 0

First, you subtract 2x on both sides
$- 3y = - 2x - 15$

divided on both sides by -3
$y = \frac{ - 2}{ - 3} x - \frac{15}{ - 3}$

$y = \frac{2}{3} x + 5$

algol [13]3 years ago

6 0

First question!

To get slope intercept form from standard form or any other form, we just solve for y.

2x - 3y = -15

Add 3y to both sides and add 15 to both sides,

2x + 15 = 3y

Divide both sides by 3 for our answer,

Answer: y = (2/3) x + 5

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A sum of money is placed at simple interest for 3 years at 10% annum and then the amount is invested for 3 years at the same rat

fgiga [73]

Answer:

Initial principal -$300,000

Investment amount after yr 3-$390,000

Final investment amount, after 6 yrs-$519,090

Step-by-step explanation:

Let X be the amount initially invested.

#The amount after 3 yrs of simple interest is calculated as:

$I=PRT\\\\A=P+I\\\\A=X+X\times 0.1\times 3\\\\A=1.3X$

#The amount after 5 yrs is calculated by compounding the amount after 3 yrs for 2 yrs at 10%:

$A=P(1+i)^2\\\\471900=1.3X(1.1)^2\\\\471900=1.573X\\\\X=300000$

Hence, the amount initially invested as $300,000

#Amount of invested after 6 yrs is therefore:

$A=P(1+i)^n\\\\=471900\times1.1\\\\=519090$

Hence, the total amount of the investment after 6 yrs is $519,090

#Substitute X in simple interest equation to find amount after 3 yrs of simple interest:

$I=PRT\\\\A=P+I\\\\A=X+X\times 0.1\times 3\\\\A=1.3X\\\\=1.3\times 300000\\\\=390000$

Hence, the total amount of the investment after first 3 yrs is $390,000

3 0

4 years ago

A bag of fruit contains 4 apples, 1 plum, 2 apricots, and 3 oranges. Pieces of fruit are drawn twice with replacement. What is P

bezimeni [28]

Since there is replacement, drawings are independent which means that the result of one of them does not affect the others.
Probability of drawing an apple is 4/10 (4 apple out of 10 fruits)
Probability of drawing an apricot is 2/10
Probability on one happening consecutively to the other (thanks to independence) is 4/10*2/10=8/100
Which can be simplified to 2/25

6 0

3 years ago

I need help asap pls

fomenos

The coefficent is 5, since it’s placed before the variable.

4 0

3 years ago

The mass of 5m^3 of copper is 44800kg. Work out the density of copper.

snow_tiger [21]

Okay so

Density= mass/volume

44800 kg/5m^3 = 8960kg/m^3
which units are preferred?

1000g/kg
1000000 cm ^3/ m^3

8 0

4 years ago

The box plots compare the number of calories in each snack pack of crackers and cookies.

Nikitich [7]

Answer:

4th statement is true.

Step-by-step explanation:

We have been two box plots, which represents the number of calories in each snack pack of crackers and cookies. We are asked to find the correct statement about our given box plots.

1. More packets of crackers have 80 calories than any other number of calories.

We can see that median of box plot representing calories of cookies is 80. This means that half of the packets of crackers have less than 80 calories and half of the packets have more than 80 calories, therefore, 1st statement is false.

2. The value 70 is an outlier for the number of calories in the cookie pack.

Since an outlier is 1.5 times the interquartile range.

$IQR=Q_3-Q_1$

$\text{IQR of cookie packs}=105-90$

$\text{IQR of cookie packs}=15$

$\text{Lower outlier}=Q_1-(1.5*IQR)$

$\text{Lower outlier}=90-(1.5*15)$

$\text{Lower outlier}=90-22.5$

$\text{Lower outlier}=67.5$

Since any number less than 67.5 will be an outlier and 70 is grater than 67.5, therefore, 70 is not an outlier in number of calories in cookie packs and 2nd statement is false.

3. The upper quartile of the cookie data is equivalent to the maximum in the cracker data.

We can see that upper quartile of cookie data is 105 and the maximum in cracker data is 100. Since 105 is greater than 100, therefore, 3rd statement is false.

4. The number of calories in each pack of cookies has a greater variation than the number of calories in each pack of crackers.

Since range and IQR are good measures of variation of box-plots, so we will find the range and IQR of our both box-plots.

We have already seen that IQR of cookie packs is 15.

$\text{IQR of cracker packs}=85-75$

$\text{IQR of cracker packs}=10$

$\text{Range}=\text{Maximum value - Minimum value}$

$\text{Range of calories in cracker packs}=100-70$

$\text{Range of calories in cracker packs}=30$

$\text{Range of calories in cookie packs}=115-70$

$\text{Range of calories in cookie packs}=45$

We can see that the range of calories in cookie packs (45) is greater than range of calories in cracker packs (30) and IQR of calories in cookie packs (15) is greater than IQR of calories in cracker packs (10), therefore, 4th statement is true.

3 0

4 years ago

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