Liquid measurements charts

OLEGan [10]

Answer:

A) The number line goes from negative 8 to positive 8. At 0, there is an open circle. The number line is shaded to the left of 0 and on the left end of the shaded line there is a left-facing arrow.

Step-by-step explanation:

Given inequality: x < 0

open circle: < or >

filled circle: ≤ or ≥

Therefore, for x < 0 there will be an open circle at 0.

< means less than, so the number line will be shaded to the left of 0 and there will be a left-facing arrow on the end of the shaded line.

7 0

3 years ago

How do I graph this someone plz tell me.

hodyreva [135]

Easy. your starting point is going to be at -2 on the y-axis. then from that point (-2) you're going to go down 1 and then over 2. then draw a straight line through those two points. The line should be a negative line.

7 0

4 years ago

7/8 as a sum of fractions

Ratling [72]

(I am not sure if this is what you are looking for)

7/8 is seven eights, so we can break it into 7 parts.

$\frac{1}{8} + \frac{1}{8} + \frac{1}{8} + \frac{1}{8} + \frac{1}{8} + \frac{1}{8} + \frac{1}{8} = \frac{7}{8}$

Hope this helps, have a nice day!

3 0

3 years ago

Let F = (2, 3). Find coordinates for three points that are equidistant from F and the y-axis. Write an equation that says P = (x

True [87]

Answer:

The equation that says P is equidistant from F and the y-axis is $P(x,y) =\left(1,\frac{3+y'}{2} \right)$ .

(1, 0), (1, 3/2) and (1,6) are three points that are equdistant from F and the y-axis.

Step-by-step explanation:

Let $F(x,y) = (2,3)$ and $R(x,y) =(0, y')$ , where $P(x,y)$ is a point that is equidistant from F and the y-axis. The following vectorial expression must be satisfied to get the location of that point:

$F(x,y)-P(x,y) = P(x,y)-R(x,y)$

$2\cdot P(x,y) = F(x,y)+R(x,y)$

$P(x,y) = \frac{1}{2}\cdot F(x,y)+\frac{1}{2} \cdot R(x,y)$ (1)

If we know that $F(x,y) = (2,3)$ and $R(x,y) = (0,y')$ , then the resulting vectorial equation is:

$P(x,y) = \left(1,\frac{3}{2} \right)+\left(0, \frac{y'}{2}\right)$

$P(x,y) =\left(1,\frac{3+y'}{2} \right)$

The equation that says P is equidistant from F and the y-axis is $P(x,y) =\left(1,\frac{3+y'}{2} \right)$ .

If we know that $y_{1}' = -3$ , $y_{2}' = 0$ and $y_{3}' = 3$ , then the coordinates for three points that are equidistant from F and the y-axis:

$P_{1}(x,y) = \left(1,\frac{3+y_{1}'}{2} \right)$

$P_{1}(x,y) = (1,0)$

$P_{2}(x,y) = \left(1,\frac{3+y_{2}'}{2} \right)$

$P_{2}(x,y) = \left(1,\frac{3}{2} \right)$

$P_{3}(x,y) = \left(1,\frac{3+y_{3}'}{2} \right)$

$P_{3}(x,y) = \left(1,6 \right)$

(1, 0), (1, 3/2) and (1,6) are three points that are equdistant from F and the y-axis.

7 0

3 years ago

Suppose that prices of a certain model of new homes are normally distributed with a mean of $150,000. Use the 68-95-99.7 rule to

konstantin123 [22]

Answer:

C. 47.5%

Step-by-step explanation:

The summary of the given statistics include:

mean =150000

standard deviation: 1200

The objective is to use tributed with a mean of $150,000. Use the 68-95-99.7 rule to find the percentage of buyers who paid: between $150,000 and $152,400

The z score formula can be use to calculate the percentage of the buyer who paid.

$z = \dfrac{X - \mu}{\sigma}$