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stepan [7]
3 years ago
8

Can someone help me with this

Mathematics
2 answers:
Helga [31]3 years ago
5 0

Answer:

C

Step-by-step explanation:

1. Absolute values are in the shape of a V, so the answer is automatically C.

2. If you did not know that, you can see that the graph is a function because it passes the vertical line test. This rules out option A. By looking at the graph, you can see it passes the x-axis twice, meaning that it has 2 x-intercepts. This rules out option B. X-intercepts always have a y-coordinate of 0, so we can rule out option D. The only option left after this is C.

Soloha48 [4]3 years ago
5 0
The answer is going to be C :)
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there are 124 students in the band. there are 12 more boys than girls in the band. how many boys and how many girls are in the b
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3 years ago
3/28 of the animals are birds. 4/15 are birds of prey. What fraction of the animals are birds of prey.
vova2212 [387]
Let's call animals "a", and birds "b", birds of prey, "p"

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3 years ago
There are 3 red marbles, 5 green marbles, and 2 blue marbles in a jar. Event A is defined as drawing a red marble from the jar o
Anastaziya [24]

P(B/A) is \frac{5}{9} in the simplest form

Step-by-step explanation:

Let us explain how to solve the problem

  • P(B|A) is called the "Conditional Probability" of B given A
  • Conditional probability is the probability of one event occurring with some relationship to one or more other events that means event A has already happened, now what is the chance of event B
  • The formula for conditional probability is P(B|A) = P(A and B)/P(A), where P(A and B) is P(A) . P(B given A occurred)

∵ There are 3 red marbles, 5 green marbles, and 2 blue

   marbles in the jar

∴ The total number of the marbles in the jar = 3 + 5 + 2 = 10

∵ Two marbles are drawn from the bag, one after the other without

   replacement

- That means red is already occurred when green is happened,

  so it is a "Conditional Probability" of green given red

  P(B/A) = P(A and B)/P(A)

∵ Event A is defined as drawing a red marble from the jar on

   the first draw

∴ P(A) = P(red)

∵ P(red) = \frac{3}{10}

∴ P(A) = \frac{3}{10}

∵ Event B is defined as drawing a green marble on the second draw

∴ P(B) = P(green)

- The number of marbles after the red is chosen is 9

∵ P(green) = \frac{5}{9}

∴ P(B) = \frac{5}{9}

- Find P( A and B)

∴ P(A and B) = ( \frac{3}{10} ) . ( \frac{5}{9} )

∴ P(A and B) = \frac{15}{90}

- Simplify the fraction by divide up and down by 15

∴ P(A and B) = \frac{1}{6}

∵ P(B|A) = P(A and B)/P(A)

- Substitute the values of P(A and B) and P(A) in the rule above

∴ P(B/A) = \frac{\frac{1}{6}}{\frac{3}{10}}

- Simplify the fraction

∵ \frac{1}{6} ÷ \frac{3}{10} = \frac{1}{6} × \frac{10}{3} = \frac{10}{18}

- Divide up and down by 2

∴ P(B/A) = \frac{5}{9}

P(B/A) is \frac{5}{9} in the simplest form

Learn more:

You can learn more about probability in brainly.com/question/10744457

#LearnwithBrainly

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