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3 years ago

Tom read 20 books, 12 magazines, and 18 newspaper articles last year.

Mathematics

2 answers:

neonofarm [45]3 years ago

8 0

Answer: 24% of the books read are magazine

Step-by-step explanation:sum of the books read is 20+12+18=50 books.

Therefore 12 of the books are magazine.

Then, 12 of 50 =24%( 12÷50)× 100/1 = 24%

Verizon [17]3 years ago

6 0

Numbers of books = 20+12+18= 50
% magazine = 12/50 x100 = 24%

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Find the cosine of each acute angle

Lemur [1.5K]

Answer:

cos P = 53 degrees

cos Q = 37 degrees

Step-by-step explanation:

cos P = $\frac{adjacent}{hypothenuse}$

cos P = $\frac{24}{40}$

cos P = 0.60

Cos-1 of 0.60 is 53.13 (round to the nearest whole number)

cos P = 53 degrees

cos Q = $\frac{adjacent}{hypothenuse}$

cos Q = $\frac{32}{40}$

cos Q = 0.80

Cos of 0.80 is 36.86 (round to the nearest whole number)

cos Q = 37 degrees

To check anser:

90 + 53 + 37 = 180

180 = 180

4 0

2 years ago

Two point particles are attached to each other via a light in-extensible string that passes over a ring hanging from the ceiling

arlik [135]

a. The expression for the tension in the string is T = mg

b. The expression for the tension in the chain is T = 2mg

To solve the problem, we need to know what tension is.

<h3>What is tension?</h3>

This is the opposing force in a stretched material.

<h3>a. Tension in the string</h3>

The expression for the tension in the string is T = mg

Since the string supports the weight of the object, the tension in the string equals the weight of the particle.

Let

T = tension in sring and
W = weight of particle = mg where
m = mass of particle and
g = acceleration due to gravity

So, T = W

T = mg

So, the expression for the tension in the string is T = mg

<h3>b. Tension in chain</h3>

The expression for the tension in the chain is T = 2mg

<h3 />

Since the chain supports both strings, the tension in the chain equals the tension in both strings.

Let

T' = tension in chain and
T = tension in each string

So, T' = T + T

T' = 2T

T' = 2W

T' = 2mg

So, the expression for the tension in the chain is T = 2mg

<h3 />

Learn more about tension here:

brainly.com/question/24994188

5 0

2 years ago

What is the unit rate for 98.4 miles on 4.8 gallons of gas?<br><br> 2.05<br> 20.5<br> 25<br> 205

igor_vitrenko [27]

20.5 is the answer because when you divide 98.4 by 4.8 you get 20.5 as the answer

3 0

3 years ago

A pet store contains 35 light green parakeets (14 females and 21 males) and 44 sky blue parakeets (28 females and 16 males). You

snow_tiger [21]

You can use this formula <span>P(AorB) = P(A) + P(B) - P(AandB)

Given:
35 LG (14 F & 21 M)
44 SB (28 F & 16 M)

Req:
- the probability that it is a female (F) or a sky blue (SB)

Sol:
</span>P(F or SB) = P(F) + P(SB) - P(F and SB)
= [(14 F + 28 F)/(35 + 44)] + [(44 SB)/(35 + 44)] - [(28 F)/(35 + 44)]
= 53.16 + 55.70 - 35.44
= 73.42%

You have to deduct 28 female parakeets from 44 sky blue parakeets because the 28 parakeets are already accounted for in the female parakeets. You can also think of how many ways you can choose a female parakeet and a sky blue parakeet. Add all female parakeets (14 + 28) = 42. Sky blue parakeet equaled to 44. Minus the 28 female parakeets included in the sky blue parakeet to avoid double counting. 42 + 44 - 28 = 58 divided by 79 (35 + 44) total parakeets = 73.42%

7 0

3 years ago

Pls help me on this math watch!!! this is non calculator

Andru [333]

The height of the cone is 4 cm (approx).

Step-by-step explanation:

Given,

The radius (r) of the cone = 4.96 cm

Volume (V) = 102 cm³

To find the height (h) of the cone.

Formula

The volume of a cone V = $\frac{1}{3}$ πr²h

Now,

According to the problem,

$\frac{1}{3}$ πr²h = 102

or, $\frac{1}{3}$ × $\frac{22}{7}$ ×(4.96)²h= 102

or, h = $\frac{102X7X3}{4.96^{2}X22 }$

or, h = 3.95 = 4 (approx)

so,

Height = 4 cm (approx)

8 0

3 years ago