6/8 of the cookies where shaped like circles and 2/8 of the cookies where shaped like squares *sorry if I’m wrong*
Step-by-step explanation:
use the steps of simultaneous
elimination steps
First we get the value of y in terms of x
We have 2x + y + 9 = 0
We transpose 2x and 9 to the other side so we could get the value of y being:
y = - 2x - 9
Now that we have the value of y we can substitute it to the first equation
6x - 3y + 10 = 0
6x - 3 (-2x - 9) + 10 = 0
Simplifying the inside of the parentheses we would have
6x - (3)(-2x) - (3)(-9) + 10 =0
6x + 6x + 27 + 10 = 0
Combining similar terms we would get
12x + 37 = 0
We transpose 37 to the other side for easier simplification
12x = - 37
We divide both sides by 12 to get the value of x
12x/12 = - 37/12
Since 12/12 is equal to 1 our value of x would be
x = - 37/12
Or simply x = - 3.0833
Now that we know the value of x we can use it to obtain the value of y
y = - 2x - 9
y = - 2(-37/12) - 9
y = 37/6 - 9
y = - 17/6
Or in decimal y = - 2.8333
Final values of x and y would be
x = - 3.0833
y = - 2.8333
Answer:
The diameter decreases at a rate of 0.143cm/min when it is of 10 cm.
Step-by-step explanation:
Surface area of an snowball:
An snowball has spherical format. The surface area of an sphere is given by:

In which d is the diameter of the sphere.
In this question:
We need to differentiate S implicitly in function of time. So

Surface area decreases at a rate of 9 cm2/min
This means that 
At which the diameter decreases when the diameter is 10 cm?
This is
when
. So




Area in cm², so diameter in cm.
The diameter decreases at a rate of 0.143cm/min when it is of 10 cm.
Answer:
5.48% of the people in line waited for more than 28 minutes
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean waiting time of 20 minutes with a standard deviation of 5 minutes.
This means that 
What percentage of the people in line waited for more than 28 minutes?
The proportion is 1 subtracted by the p-value of Z when X = 28. So



has a p-value of 0.9452.
1 - 0.9452 = 0.0548.
As a percentage:
0.0548*100% = 5.48%
5.48% of the people in line waited for more than 28 minutes