It is given that the length of triangle base is 26, then let ABC be the triangle and BC be the base of the triangle=26.Let DE be the parallel line to the base that divides triangle ABC into two equal area parts.

Now, Let AD=a, DB=b, DE=c, AE=d and EC=e, then

Since, triangle ABC is similar to triangle ADE, thus using basic proportions, we get

$\frac{AD}{AB}=\frac{DE}{BC}=\frac{AE}{AC}$

$\frac{AD}{AD+DB}=\frac{DE}{BC}=\frac{AE}{AE+EC}$

$\frac{a}{a+b}=\frac{c}{26}=\frac{d}{d+e}$

Taking the first two equalities,we get

$\frac{a}{a+b}=\frac{c}{26}$

$c=\frac{26a}{a+b}$

Thus, the length of the segment between triangle legs is $\frac{26a}{a+b}$

7 0

4 years ago

Mr. Dylan asks his students throughout the year to record the number of hours per week they spend practicing math at home. At th

hoa [83]

Answer:

The second plot.

Step-by-step explanation:

In the picture attached, the scatter plots are shown.

The second plot has minimum residuals and its residuals are randomly distributed. Residual is computed as follows:

residual = measured - predicted

It easy to see that residuals of the first option are greater than the second option.

Line of the second option is better than those from third and fourth options because residuals of the second option are randomly distributed, while in the third option, residuals are mostly negative; and in the fourth option, they are mostly positive.

4 0

4 years ago