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vichka [17]
3 years ago
12

I need help please help

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
5 0

Answer:

the second one

Step-by-step explanation:

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Leon earns $14 an hour how much does he earn in 4 weeks If he works 12 hours each week
Rudiy27

Answer:

14$ times 12 hours =

168$

168$ times 4 weeks =  672$

Step-by-step explanation:

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4 years ago
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Sergio039 [100]

Answer:

Subtract 6

Step-by-step explanation:

The answer is subtract six because you subtract six every time in the pattern.

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Why would understanding perpendicular and parallel lines be extremely important to someone in construction? Provide an example o
Tems11 [23]

Understanding perpendicular and parallel lines are extremely important, especially in the engineering field when building infrastructures or houses because they need to calculate how they will keep a building stable. For example, bridges we see have a lot of perpendicular and parallel lines, that's because without those the bridge can't hold itself up, it needs support from the metals that are parallel and perpendicular.

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5 0
3 years ago
(01.03. 106, 1.08 HC)
zlopas [31]

Answer:

  A) see attached for a graph. Range: (-∞, 7]

  B) asymptotes: x = 1, y = -2, y = -1

  C) (x → -∞, y → -2), (x → ∞, y → -1)

Step-by-step explanation:

<h3>Part A</h3>

A graphing calculator is useful for graphing the function. We note that the part for x > 1 can be simplified:

  \dfrac{-x^2+x+2}{x^2-3x+2}=-\dfrac{(x-2)(x+1)}{(x-2)(x-1)}=-\dfrac{x+1}{x-1}\quad x\ne 2

This has a vertical asymptote at x=1, and a hole at x=2.

The function for x ≤ 1 is an ordinary exponential function, shifted left 1 unit and down 2 units. Its maximum value of 3^-2 = 7 is found at x=1.

The graph is attached.

The range of the function is (-∞, 7].

__

<h3>Part B</h3>

As we mentioned in Part A, there is a vertical asymptote at x = 1. This is where the denominator (x-1) is zero.

The exponential function has a horizontal asymptote of y = -2; the rational function has a horizontal asymptote of y = (-x/x) = -1. The horizontal asymptote of the exponential would ordinarily be y=0, but this function has been translated down 2 units.

__

<h3>Part C</h3>

The end behavior is defined by the horizontal asymptotes:

  for x → -∞, y → -2

  for x → ∞, y → -1

7 0
2 years ago
The linear combination method gives a solution of (–4, 2) for which of these systems of linear equations?
otez555 [7]

The solution (-4,2) satisfies for the system of linear equations 3x + 13y = 14; 6x + 11y = -2

<u>Step-by-step explanation:</u>

Step 1:

Given detail is the solution of the equations (-4, 2) ie, x= - 4 and y = 2

This implies that this solution should satisfy the given linear equations.

Step 2:

Substitute values of x and y in the equations and verify whether the right hand side equals the left hand side.

System 1 Eq(1) ⇒ LHS = 3(-4) + 13 (2) = -12 + 26 = 14 = RHS

System 1 Eq(2) ⇒ LHS = 6(-4) + 11(2) = -24 + 22 = -2 = RHS

Therefore, the first system of linear equations satisfy the condition.

4 0
4 years ago
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