Question

For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 40 N acts on a certain object, the acceleration
of the object is 10 m/s. If the acceleration of the object becomes 6 m/s?, what is the force?

Answer 1

Answer:

New force = 24 N

Step-by-step explanation:

The force acting on the object varies directly with the object's acceleration

i.e.

$\dfrac{F_1}{F_2}=\dfrac{a_1}{a_2}$ ...(1)

We have,

F₁ = 40 N, a₁ = 10 m/s², a₂ = 6 m/s₂, F₂ =?

Put all the values in equation (1).

$F_2=\dfrac{F_1a_2}{a_1}\\\\F_2=\dfrac{40\times 6}{10}\\\\F_2=24\ N$

So, the new force becomes 24 N.