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3 years ago

4 = -8 - x What is x?

Mathematics

2 answers:

Stels [109]3 years ago

7 0

Answer:

Step-by-step explanation:

a negative x negative is always a positive

a negative x positive is negative

a positive x positive is negative

jok3333 [9.3K]3 years ago

7 0

Answer:

x=-12

Step-by-step explanation:

4 = -8 - x

First, step +8 to get it to the other side of the question, then it will be 12 = -x

to get x move the negative to the other side x = -12

Can i have brainly please

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List 3 values that would make this inequality true 43 < y -30

prohojiy [21]

43 < y - 30
add 30 to both sides
73 < y

y can be anything that is greater than 73
so it could be...
101, 74, 90, 75, 980767, 5674, etc.

Hope this helps!

4 0

2 years ago

What is the inverse function of f(x) = 25x-3?

Harrizon [31]

Answer:

The answer is

Step-by-step explanation:

$f(x) = 25x - 3$

To find the inverse of f(x) , equate f(x) to y

That's

y = f(x)

We have

$y = 25x - 3$

Next interchange the terms that's x becomes y and y becomes x

$x = 25y - 3$

Next solve for y

Move 3 to the other side of the equation

That's

$25y = x + 3$

Divide both sides by 25

$\frac{25y}{25} = \frac{x + 3}{25}$

We have the final answer as

${f}^{ - 1} (x) = \frac{x +3 }{25}$

Hope this helps you

5 0

2 years ago

Table 2

astra-53 [7]

The answer is 3rd one

3 0

3 years ago

Read 2 more answers

If five numbers are selected at random from the set {1,2,3,...,20}, what is the probability that their minimum is larger than 5?

Zanzabum

Answer:

the probability that their minimum is larger than 5 is 0.2373

Step-by-step explanation:

For calculate the probability we need to make a división between the total ways to selected the 5 numbers and the ways to select the five numbers in which every number is larger than 5.

So the number of possibilities to select 5 numbers from 20 is:

20 * 20 * 20 * 20 * 20

First number 2nd number 3rd number 4th number 5th number

Taking into account that a number can be chosen more than once, and the order in which you select the numbers matters, for every position we have 20 options so, there are $20^{5}$ ways to select 5 numbers.

Then the number of possibilities in which their minimum number is larger than 5 is calculate as:

15 * 15 * 15 * 15 * 15

First number 2nd number 3rd number 4th number 5th number

This time for every option we can choose number from 6 to 20, so we have 15 numbers for every option and the total ways that satisfy the condition are $15^{5}$

So the probability P can be calculate as:

$P=\frac{15^{5} }{20^{5} } \\P=0.2373$

Then the probability that their minimum is larger than 5 is 0.2373

7 0

2 years ago

Can you plz help me by solving the equation and showing how you got the answer

hoa [83]

Answer:80

Step-by-step explanation: It is 80

5 0

2 years ago

Read 2 more answers