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miss Akunina [59]
3 years ago
14

PLEASE HELP 30 POINTS Find the angle measure indicated. 140 ° ?

Mathematics
1 answer:
Artist 52 [7]3 years ago
8 0

Answer:

134%

Step-by-step explanation:

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An executive in an engineering firm earns a monthly salary plus a Christmas bonus of 7100 dollars. If she earns a total of 90400
photoshop1234 [79]

90,400-7,100=83,300

83,300/12=6,941.66667

Monthly Salary Rounded: 6,941.67

5 0
3 years ago
In rectangle PQRS, PR = 18x – 28 and QS = x + 380. Find the value of x and the length of each diagonal.
chubhunter [2.5K]

Answer:

x = 24, PR = 404, QS = 404

Step-by-step explanation:

PR and QS are both diagonals of the rectangle. The diagonals of a rectangle bisect each other and are of equal length. Thus, we can say:

PR = QS

18x - 28 = x + 380

Solving for x, we get:

18x - x = 380 + 28

17x = 408

x = 408/17

x = 24

Thus, PR = 18(24) - 28 = 404  and  QS = 24 + 380 = 404

Third choice is right.

7 0
3 years ago
A right triangle has a leg of 11 cm and a hypotenuse of 17 cm.
Vedmedyk [2.9K]
The answer would be the second option, 13.0 cm.

To find the missing length of the leg, you would use the pythagorean theorem and substitute your inputs in.

a^2+b^2=c^2
11^2+b^2=17^2
121+b^2=289
b^2=168
b=12.96 
b=13.0 cm (rounded up)
4 0
3 years ago
Read 2 more answers
Plz help me thanks very nuch whoever helped me​
photoshop1234 [79]

Answer:

(1) 56 miles/hour

Step-by-step explanation:

We need to find the average rate of change from t = 2 to t = 9.

At t = 2 hours, d = 106 miles.

At t = 9 hours, d = 498 miles.

The average rate of change in function f(x) from x = a to x = b is

[f(b) - f(a)]/(b - a)

average rate of change from t = 2 to t = 9 =

(498 - 106)/(9 - 2) = 392/7 = 56

Answer: (1) 56 miles/hour

7 0
3 years ago
i have 60+8x=108 x=6 but for the other equation i dont know how to get rid of the 3x to solve for the y.
LUCKY_DIMON [66]
Angle a is congurent to angle e, so 60+8x=108
same with c and g.
so 8y-3x=62
just plug in x for there (6)
so 8y-24=62
then 8y=88
y=11
8 0
4 years ago
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